Subtract. 5 27x

How much is 1 1/4 + 3/4 + 1 1/3 step by step

dangina [55]

Answer:

3 1/3

Step-by-step explanation:

Step 1 is to look at the problem.

Here, you notice that the first two numbers have fractions that are quarters. The total of those two fractions is 1/4 + 3/4 = 4/4 = 1.

So, the sum of the first two numbers is ...

1 1/4 + 3/4 = 1 +(1/4 +3/4) = 1 +1 = 2

Step 2 is to add the next mixed number, which has a fraction with a different denominator. Since you have no fractions to add at this point, the sum is just ...

2 + 1 1/3 = 3 1/3

_____

Comment on adding fractions

Generally, adding fractions requires you determine a common denominator. Often, you are asked to find the least common denominator, but that isn't necessary. Sometimes that can save the work of reducing the fraction that results, but sometimes it makes more work.

Here, a common denominator for fourths and thirds would be twelfths:

1/4 = 3/12

1/3 = 4/12

However, since adding the fourths results in an integer, no common denominator is necessary.

3 0

4 years ago

How do you solve this?

vovangra [49]

a) C = 40 + 30t

b) 280 = 40 + 30t

30t = 240

t = 8

The plumber worked 8 hours

4 0

3 years ago

Read 2 more answers

Which coordinate plane contains the points ( 2,3.5) and (-0.5,4) ? Ill give brainliest

Nastasia [14]

Answer:

D

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Three bouquets of flowers are ordered at a florist. 3 roses, 2 carnations, and 1 tulip cost $14. 6 roses, 2 carnations, and 6 tu

STALIN [3.7K]

cost of 1 rose = $ 3

cost of 1 carnation = $ 1

cost of 1 tulip = $ 3

Solution:

Let "r" be the cost of 1 rose

Let "c" be the cost of 1 carnation

Let "t" be the cost of 1 tulip

3 roses, 2 carnations, and 1 tulip cost $14

So we can frame a equation as:

3 roses x cost of 1 rose + 2 carnations x cost of 1 carnation + 1 tulip x cost of 1 tulip = $ 14

$3 \times r + 2 \times c + 1 \times t = 14$

3r + 2c + 1t = 14 ----- eqn 1

6 roses, 2 carnations, and 6 tulips cost $38

So we can frame a equation as:

6 roses x cost of 1 rose + 2 carnations x cost of 1 carnation + 6 tulip x cost of 1 tulip = $ 38

$6 \times r + 2 \times c + 6 \times t = 38$

6r + 2c + 6t = 38 ------ eqn 2

1 rose, 12 carnations, and 1 tulip cost $18

So we can frame a equation as:

1 rose x cost of 1 rose + 12 carnations x cost of 1 carnation + 1 tulip x cost of 1 tulip = $ 18

$1 \times r + 12 \times c + 1 \times t = 18$

r + 12c + t = 18 ----- eqn 3

Let us solve eqn 1 and eqn 2 and eqn 3 to find values of "r" "c" "t"

3r + 2c + 1t = 14 ----- eqn 1

6r + 2c + 6t = 38 ------ eqn 2

r + 12c + t = 18 ----- eqn 3

From eqn 1,

3r = 14 - 2c - t

$r = \frac{14 - 2c - t}{3}$

Substitute the above value of r in eqn 2

$6(\frac{14 - 2c - t}{3})+ 2c + 6t = 38\\\\28 - 4c - 2t + 2c + 6t = 38\\\\-2c +4t = 10\\\\-2c = 10 - 4t\\\\2c = 4t - 10\\\\c = 2t - 5$

Substitute c = 2t - 5 and $r = \frac{14 - 2c - t}{3}$ in eqn 3

$12(2t - 5) + \frac{14 - 2c - t}{3} + t = 18\\\\24t - 60 + \frac{14-2(2t - 5) - t}{3} + t = 18\\\\72t - 180 + 14 - 4t +10 - t + 3t = 54\\\\70t = 54 + 180 - 14 -10\\\\70t = 210\\\\t = 3$

Substitute t = 3 in c = 2t - 5

c = 2(3) - 5

Substitute t = 3 and c = 1 in $r = \frac{14 - 2c - t}{3}$

$r = \frac{14 - 2(1) - 3}{3}\\\\r = \frac{14 - 2 - 3}{3}\\\\r = \frac{9}{3} = 3$

Summarizing the results:

cost of 1 rose = $ 3

cost of 1 carnation = $ 1

cost of 1 tulip = $ 3

6 0

3 years ago

I need help finding X please

Vedmedyk [2.9K]

Hello

This is a right angle as you can see by the small square at the bottom. So this means that it is 90 degrees.

Because we already know part of the 90 degrees, we can do 90-50 degree which leave us with 40 degrees.

So as we look at 8x, it needs to equal 40

- 8x=40 divide both sides by 8

- x=5

Hope this helps!

7 0

4 years ago

Subtract. 5 27x - 75x