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Ivenika [448]
3 years ago
14

Subtract. 5 27x - 75x

Mathematics
1 answer:
Nadya [2.5K]3 years ago
5 0
I think the answer is x=0 the equation is not set up clearly
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The Ohio Department of Agriculture tested 203 fuel samples across the state
Rus_ich [418]

Answer:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

Step-by-step explanation:

Previous concept

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The proportion estimated would be:

\hat p = \frac{14}{105}= 0.133

And that represent the proportion of failures.

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

If we replace the values obtained we got:

0.133 - 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.0475

0.133 + 2.58\sqrt{\frac{0.133(1-0.133)}{105}}=0.2185

The 99% confidence interval would be given by (0.0475;0.2185)

3 0
3 years ago
Read 2 more answers
I Need Some Help!!!!!!!!!
ehidna [41]

Answer:

median = 50

difference in the quartiles = 45

Step-by-step explanation:

The median amount is the line in the middle of the box

The median is 50

The difference between the upper quartile and the lower quartile is the difference between the right end of the box and the left end of the box

65-20 = 45

4 0
2 years ago
Colin took out a loan with a principal of $32,800. After five years, the interest and the principal totaled $48,872. If Colin ma
yulyashka [42]
C hope that can help you
8 0
3 years ago
Which equation should be used to calculate the 43rd partial sum for the arithmetic sequence.
MariettaO [177]

Answer: First Option : Sₙ= n/2(a₁ + aₙ)

Step-by-step explanation:

The nth partial sum of an arithmetic sequence or the sum of the first n terms of the arithmetic series can be defined as the sum of a finite number of term in an arithmetic sequence.

It is calculated using the formula:

Sₙ= n/2(a₁ + aₙ)

Where :

a₁ = First term

aₙ = last term

n = number of terms

6 0
2 years ago
Really need help on my correction if anyone know please help!!
Olin [163]
Answers: 
<u>Question 19:</u> 177 bpm
<u>Question 20:</u> 95˚F

Explanations:
<u>Question 19:</u>
You had the formula set up properly like this:
R =  \frac{885 \sqrt{25} }{25}  =  \frac{885(5)}{25}  =  \frac{4425}{25} 
This is where you went wrong - I don't know exactly what you did, but your division of 4425 ÷ 25 is wrong. You should have ended up with 177 which is the correct answer. 
<u>Question 20:</u>
You had the formula set up correctly again, and merely used the wrong sign when adding 32. 
F =  \frac{9(35)}{5} + 32 =  \frac{315}{5} + 32
This is where you went wrong. You subtracted 32 from 63 when you should have added it. (See red circle on your subtraction.)
63 + 32 = 95˚F
7 0
3 years ago
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