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MaRussiya [10]
3 years ago
10

Why does the vertical line test determine if the graph represents a function?

Mathematics
2 answers:
Irina-Kira [14]3 years ago
6 0
<span>the vertical line test is a visual way to determine if a curve is a graph of a function or not.</span>
Georgia [21]3 years ago
5 0
A function can only have one output per input. For an xy function, this means that for every x, there can only be one y. If you do the vertical line test and it crosses a line more then once, then that means that the graph has more than one y value for a single x value, meaning it is not a function.
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Jacob bought one bulb of elephant garlic for $2. How many bulbs can Stephanie buy if she has $12?
Marysya12 [62]

Answer:

She can buy six bulbs of garlic

Step-by-step explanation:

Well you know that each bulb of garlic is 2 dollars.  You also know that Stephanie has 12 dollars.  In order to solve this you need to take the amount of money Stephanie has and divide it by the price per bulb in order to find out how many bulbs she can buy.

12/2 = 6

She can buy 6 bulbs of garlic

5 0
3 years ago
Read 2 more answers
[GEOMETRY] please help, i keep getting 622, thats not one of the answers
Flauer [41]
It is 622 . 622 is 198*3.14
6 0
3 years ago
Will someone please help me understand this?
mario62 [17]

Option A:

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Solution:

In the quadrilateral, the coordinates of J is (1, 6) and L is (7, 3).

So that, x_1=1, y_1=6, x_2=7, y_2=3

To find the length of the diagonal JL.

Using distance formula:

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

d=\sqrt{(3-6)^2+(7-1)^2}

d=\sqrt{(-3)^2+(6)^2}

d=\sqrt{9+36}

d=\sqrt{45}

d=\sqrt{3^2\times 5}

d=3\sqrt{ 5} units

The length of diagonal JL is 3 \sqrt{5} \text { units }.

Option A is the correct answer.

7 0
3 years ago
Read 2 more answers
Which type of triangle is formed with the points A(1, 7), B(-2, 2), and C(4, 2) as its vertices?
Dafna1 [17]
We will have to use the distance formula in order to determine the lengths of each side of the triangle.

Distance formula: \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2} }

Let's calculate AB first:
A (1, 7) and B (-2, 2)
A: x1 = 1 and y1 = 7
B: x2 = -2 and y2 = 2

so
\sqrt{(-2 - 1)^{2} + (2 - 7)^{2} }
\sqrt{(-3)^{2} + (-5)^{2} }
\sqrt{9 + 25 }
AB = \sqrt{34} or (rounded to the nearest tenth) ≈ 5.8

Now let's do BC:
B: x1 = -2 and y1 = 2
C: x2 = 4 and y2 = 2

So
\sqrt{(4 - -2)^{2} + (2 - 2)^{2} }
\sqrt{(6)^{2} + (0)^{2} }
BC = \sqrt{36 } or 6

Now let's do CA
C: x1 = 4 and y1 = 2
A: x2 = 1 and y2 = 7

So
\sqrt{(1 - 4)^{2} + (7 - 2)^{2} }
\sqrt{(-3)^{2} + (5)^{2} }
\sqrt{9 + 25}
CA = \sqrt{34} or (rounded to the nearest tenth) ≈ 5.8

So let's recap:

AB ≈ 5.8
BC = 6
CA ≈ 5.8

So AB and AC are the same length while BC is .2 units longer which means this is an isosceles triangle.

4 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!
laila [671]

Answer:

1). 110.8

2). 125

Step-by-step explanation:


7 0
3 years ago
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