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Colt1911 [192]
3 years ago
7

devin drew a rectangle that is 4 inches by 9 inches. it has an area of 36 square inches and a perimeter of 26 inches. which rect

angle has dimensions that give the same perimeter as devin's rectangle but has a different area? a. 2 inches by 11 inches b. 3 inches by 8 inches c. 4 inches by 12 inches d. 5 inches by 12 inches
Mathematics
1 answer:
Makovka662 [10]3 years ago
8 0
A. 2 inches by 11 inches
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leonardo recorded his speed while skateboarding and determined he was traveling 18 feet per second. how many feet could he trave
Effectus [21]

All you need to do is multiply 18*60 = 1080  feet per minute, which is really fast.

7 0
3 years ago
in a random School sampling of 50 middle school students it was found that 18 students bring their lunch to school everyday if t
dem82 [27]

Answer:

340

Step-by-step explanation:

We can see in the sample that 18/50 people bring lunches to school. If we divide 18 by 50 we get 0.36 now we know that 36% of people bring their lunches in the sample. Now we take that number and multiply it by 942.

0.36*942= 339.12 which we can round to 340

5 0
2 years ago
Help me to solve this please​
scZoUnD [109]

Answer:

-4/9

Step-by-step explanation:

We first calculate the first bracket.

[2/3-(-4/9)]

= (2/3+4/9) (we cancel out the negatives)

= (6/9+4/9) (common denominator)

= 10/9

Then we convert -2 1/2 into an improper fraction.

-2 1/2

= -5/2

Finally we calculate the division by swapping the numerator and denominator of -5/2.

10/9 / -5/2

= 10/9 * -2/5

= -20/45

= -4/9 (simplify the terms)

3 0
2 years ago
each block weighs 7 pounds and the wagon can only carry 77 pounds at a time how many blocks can you carry in the wagon at a time
Agata [3.3K]
11 blocks can be carried at a time

Hope this helps :)
4 0
3 years ago
I need help finding the range and domain, you can use the images I've included for guidance! I need this asap thank youu
SCORPION-xisa [38]

Answer:

\displaystyle Range: \\ Set-Builder\:Notation → y|1 ≥ y ≥ -1 \\ Interval\:Notation → [-1, 1] \\ \\ Domain: \\ Set-Builder\:Notation → x|x ∈ R \\ Interval\:Notation → (-∞, ∞)

Step-by-step explanation:

This is the graph of \displaystyle y = cos\:x,in which its AMPLITUDE [<em>A</em>] ALWAYS starts ONE BLOCK ABOVE the <em>midline</em><em>.</em><em> </em>In the trigonometric formula below, −C gives the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle y = Acos[Bx - C] + D

NOTE: Depending on how your trigonometric graphs are structured, your vertical shift [<em>D</em>] might tell you to space out the amplitude of the graphs alot more evenly on both ends.

<u>Extended</u><u> </u><u>Information on</u><u> </u><u>Trigonometric</u><u> </u><u>Graphs</u>

\displaystyle Vertical\:Shift = D \\ Phase\:Shift\:[Horizontal\:Shift] = \frac{C}{B} \\ Period = \frac{2}{B}π \\ Amplitude = |A|

I am joyous to assist you anytime.

7 0
3 years ago
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