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Paladinen [302]
2 years ago
9

Geometry math question no Guessing and Please show work

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
5 0
IN ORDER TO FIND THE ANSWER:

Add up two of the values. If they are greater than the third, the lengths can make up a triangle.

3 + 9 = 12
12 > 14? No

3 + 5 = 8
8 > 7? Yes

1 + 2 = 3
3 > 3? No

4 + 4 = 8
8 > 8? No

The answer would be B.
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Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
Which table contains only corresponding x - values and y - values where the value of y is 3 more than the quotient of x and 2?
melisa1 [442]

Fr like whats the answer choice

6 0
2 years ago
Read 2 more answers
Which expression is equivalent to StartFraction c squared minus 4 Over c + 3 EndFraction divided by StartFraction c + 2 Over 3 (
Firdavs [7]

Answer:

C

Step-by-step explanation:

Given:

\dfrac{c^2-4}{c+3}\div  \dfrac{c+2}{3(c^2-9)}

Changing the division to multiplication by taking the reciprocal of the second fraction.

\dfrac{c^2-4}{c+3}X  \dfrac{3(c^2-9)}{c+2}

<u>The correct option is C</u>

3 0
2 years ago
Read 2 more answers
Can someone please help! i have no clue what im doing
gulaghasi [49]

g(x) = -3x - 8


g(x) = 10

⇒ -3x - 8 = 10

⇒ -3x = 18

⇒ x= -6


g(-6) = 10 <==== answer is -6

7 0
3 years ago
Which statement is true regarding triangle TU?
blsea [12.9K]

Answer:

angle v is the smallest

Step-by-step explanation:

3 0
3 years ago
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