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Paladinen [302]
3 years ago
9

Geometry math question no Guessing and Please show work

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0
IN ORDER TO FIND THE ANSWER:

Add up two of the values. If they are greater than the third, the lengths can make up a triangle.

3 + 9 = 12
12 > 14? No

3 + 5 = 8
8 > 7? Yes

1 + 2 = 3
3 > 3? No

4 + 4 = 8
8 > 8? No

The answer would be B.
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A line goes through the point (6,-2) and has a slope of
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Answer: a = 3

Step-by-step explanation: when you multiply 6 by -3 you get -18 and if you add 16 you get -2

so the slope is -3 and the y-intercept is 16

so a*-3 + 16 = 7

by subtracting 16 on both sides you get

-3a = -9

and to get a by itself you divide -3 on both sides

a = -9/-3

a= 9/3

a = 3

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What property (associative,distributive,communitive) is 9(6+4)=(9x6)+(9x4)
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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, <em>MOE</em> = 0.04.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, <em>MOE</em> = 0.02.

The formula for margin of error is:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}

The critical value of <em>z</em> for 95% confidence interval is: z_{\alpha/2}=1.96

Compute the minimum sample size required as follows:

MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

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