Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.
8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.
The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means
(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60
Solve for <em>q</em> :
3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)
3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>
0.4<em>q</em> = 1.6
<em>q</em> = 4
Steps 4 and 5 are being used to get the equation in step 6.
Steps 5 and 7 are being used to get the equation in step 8.
Steps 8 and 6 are being used to get the equation in step 9.
In step 14, "similar argument" means to draw segment BD and follow the same logic in steps 3-12.
Answer:
2cosAcos2A, 4sinAcos^2A
Step-by-step explanation:
cos3A+cosA
2cos((3A+A)/2)cos((3A-A)/2)
2cos(4A/2)cos(2A/2)
2cosAcos2A
sin3A+sinA
2sin((3A+A)/2)cos((3A-A)/2)
2sin(4A/2)cos(2A/2)
2sin2AcosA
4sinAcos^2A
Answer:Then ask a neighbor for help
Step-by-step explanation:Hey just breath
