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vivado [14]
3 years ago
8

The measure of the missing angle is ?

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
3 0
X = 97

Working on other question.
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One fruit punch has 10% juice and another has 50%. How much of the 10% should be mixed with 30 gal of the 50% to create punch th
N76 [4]

Answer:

We combine x ounces of 100% juice

with 40-x of 10% juice

to get 40 ounces of 55% juice

 

x + 0.1(40-x) = .55(40)

x + 4 - 0.1x = 22

0.9x + 4 = 22

.09x = 18

x = 20 ounces of 100% juice

40-x = 20 ounces of 10% juice

 

We combine 20 ounces of each.

 

Step-by-step explanation:

8 0
2 years ago
Find the distance between the points (6, 5 square root 2) and (4, 3square root 2).
Sonbull [250]

The distance would be 2√3 , in other words it is 2 square root 3

4 0
2 years ago
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Can someone please explain how to simplify expressions that have negative or positive exponents
solniwko [45]

Step-by-step explanation:

I guess you just slove the exponent can I see the actual question

8 0
3 years ago
A trucking firm has a large inventory of spare parts that have been in storage for a long time. It knowsthat some proportion of
Debora [2.8K]

Answer:

0.1546\leq \widehat{p}\leq 0.3513

Step-by-step explanation:

The firm tests 75 parts, and finds that 0.25 of them are notusable

n = 75

x = 0.25 \times 75 = 18.75≈19

\widehat{p}=\frac{x}{n}

\widehat{p}=\frac{19}{75}

\widehat{p}=0.253

Confidence level = 95%

So, Z_\alpha at 95% = 1.96

Formula of confidence interval of one sample proportion:

=\widehat{p}-Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}\leq \widehat{p}\leq \widehat{p}+Z_\alpha \sqrt{\frac{\widehat{p}(1-\widehat{p}}{n}}

=0.253-(1.96)\sqrt{\frac{0.253(1-0.253)}{75}}\leq \widehat{p}\leq0.253+(1.96)\sqrt{\frac{0.253(1-0.253}{75}}

Confidence interval =0.1546\leq \widehat{p}\leq 0.3513

7 0
3 years ago
Consider the line 5x-8y=8 what is the slope of a line perpendicular to this line what is the slope of a line parallel to this li
Sophie [7]

\text{Let}\ k:y=m_1x+b_1\ \text{and}\ l:y=m_2x+b_2,\ \text{then}\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\\\l\ \parallel\ k\iff m_1=m_2\\\\\text{Convert the equation to the slope-intercept form}\ y=mx+b.\\\\5x-8y=8\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-8y=-5x+8\qquad\text{divide both sides by (-8)}\\\\y=\dfrac{5}{8}x-1\to m_1=\dfrac{5}{8}\\\\perpendicular:\ m_2=-\dfrac{1}{\frac{5}{8}}=-\dfrac{8}{5}\\\\parallel:\ m_2=\dfrac{5}{8}

8 0
3 years ago
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