You can solve this since you can develop 3 equations for your 3 unknowns. Each equation is made using the Pythagorean theorem:
1) x^2 = y^2 + 16^2
2) z^2 = y^2 + 4^2
3) (16 + 4)^2 = z^2 + x^2
Simplifying the above we get:
1) x^2 = y^2 + 256
2) z^2 = y^2 + 16
3) 400 = z^2 + x^2
We want to solve for z. There are several ways but an easy one is with substitution. Start by rearranging 2) and 3) like this:
2’) y^2 = z^2 - 16
3’) x^2 = 400 - z^2
Now we have expressed x and y in terms of z. Plug these values into the unused equation, 1), to solve for z:
1’) 400 - z^2 = z^2 - 16 + 256
2z^2 = 160
z^2 = 80
z = √80
z = √(16)(5)
z = 4√5
Answer:
22.5
Step-by-step explanation:
start by doing 4 squared, since theirs an n on the 4 you have to leave the n attatched to 16 (4 squared is 16) then you have to subtract 10 from -36 and you get 46. after you do that you have to divided 16 from both sides. witch leaves you with n= 22.5
1)u multiplies every thing in the bracket giving you 4u×-5u=22
2)multiply 4u and5u=20u
3)divide both sides by 20(u=11)
4)and that's your final answer.
Good Luck!!! Srry I don’t know!
The lateral surface area of the cylinder = 80 sq cm.
Step-by-step explanation:
Given,
The circumference of the base of the cylinder is 16 cm
So, 2 X pi X r = 16 cm ( where r be the radius of the base)
Now, the lateral surface of the cylinder = 2 X pi X r X H ( where H be the height = 5 cm)
= 16 X 5 sq cm
= 80 sq cm
Hope it helps you.
