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erik [133]
3 years ago
12

James types 84 words in 2 minutes he estimates that he has his history essay is 420 words long what is the least amount of time

james will need to type his essay
Mathematics
1 answer:
adell [148]3 years ago
4 0
84 words = 2 min
1 word = 2/84 = 1/42
420 words = 1/42 x 420 = 10 mins


Answer: 10 mins
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Nancy Wrote two equivalent expressions. If she sets them equal to each other, will them equation have one solution, no solutions
Lady_Fox [76]

The answer is infinetely many solutions.

6+6=6+6

12=12

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2 years ago
If you travel 1000 feet in 5 minutes, what is your speed in feet per minute?
Ilia_Sergeevich [38]

Answer:

200 feet per minute

Step-by-step explanation:

1000 / 5 gives us the feet per minute

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Answer:  200 feet per minute

4 0
3 years ago
The​ life, in​ years, of a certain type of electrical switch has an exponential distribution with an average life β=44. If 100 o
Bond [772]

Answer:

0.9999

Step-by-step explanation:

Let X be the random variable that measures the time that a switch will survive.

If X has an exponential distribution with an average life β=44, then the probability that a switch will survive less than n years is given by

\bf P(X

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\bf P(X

Now we have 100 of these switches installed in different systems, and let Y be the random variable that measures the the probability that exactly k switches will fail in the first year.

Y can be modeled with a binomial distribution where the probability of “success” (failure of a switch) equals 0.0225 and  

\bf P(Y=k)=\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}

where  

\bf \binom{100}{k} equals combinations of 100 taken k at a time.

The probability that at most 15 fail during the first year is

\bf \sum_{k=0}^{15}\binom{100}{k}(0.02247)^k(1-0.02247)^{100-k}=0.9999

3 0
3 years ago
Jessica and Riley are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping
bixtya [17]

Answer:

Cost of one roll of plain wrapping: \$5

Cost of one roll of holiday wrapping paper:  \$19

Step-by-step explanation:

Let be "p" the cost in dollars of one roll of plain wrapping paper and "h" the cost in dollars of one roll of holiday wrapping paper.

Based on the information given, we can set up this system of equations:

\left \{ {{5p+13h=272} \atop {11p+16h=359}} \right.

In order to solve it, we can use the Substitution method. The steps are:

1. Solve for "p" from the first equation:

5p+13h=272\\\\5p=272-13h\\\\p=\frac{272-13h}{5}

2. Substitute the above into the second equation and solve for "h":

11(\frac{272-13h}{5})+16h=359\\\\598.4-28.6h+16h=359\\\\-12.6h=359-598.4\\\\h=\frac{-239.4}{-12.6}\\\\h=19

3. Substitute the value of "h" into p=\frac{272-13h}{5}:

p=\frac{272-13(19)}{5}\\\\p=5

7 0
3 years ago
A newspaper article states that 90% of drivers in Iowa wear their seatbelt. Suppose we are interested in estimating the proporti
konstantin123 [22]

Answer:

The sample size is  n  = 3457

Step-by-step explanation:

From the we are told that

  The population proportion is  p =  0.90

  The margin of error is  E =  0.01  

From the question we are told the confidence level is  95% , hence the level of significance is    

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=>   \alpha = 0.05

Generally the sample size is mathematically represented as

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=>  n  =[  \frac{ 1.96  }{0.01} ]^2 * 0.90(1-0.90)

=>   n  = 3457

8 0
3 years ago
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