Question

Emergency!

Answer 1

Every single one of those expressions factor.  When factored, this is what we have: $\frac{(3x-7)(x+3)}{(x+3)(x-2)} * \frac{(2x-7)(x+9)}{(3x-7)(2x+7)}$.  After canceling out like factors, what we are left with is this: $\frac{1x+9}{1x-2}$.  That means that b = 9, c = 1, and d = -2