The place value of 3 in 630 is tens.
Where’s the rest of the info??
Answer:
False
Step-by-step explanation:
You can't add two different variables together
Answer:the error is when 6y=12
Step-by-step explanation:
the original problem says 4x-6y=12
so when you get rid of the 4x, it should still be -6y not positive
I’m guessing that this is for systems of equations?
n - nickels
d - dimes
These are the equations you start off with.
n = 5d-2
0.95 = 0.10d+0.05n
Substitute the top equation for n into the variable n in the bottom equation.
0.95 = 0.10d+0.05(5d-2)
Solve for d.
0.95 = 0.10d+0.25d-0.10
1.05 = 0.35d
3 = d
Substitute d into the top equation and solve for n.
n = 5(3)-2
n = 15-3
n = 12
There are 3 dimes and 12 nickels in the coin purse! Hope this helped <3