Question

100 POINTS!!! PLEASE I NEED HELP DUE TODAY!!!!

Answer 1

Using weighed averages, it is found that:

1. The final grade is 91.
2. The final grade is 66.8.
3. The higher grade would be 79.55, with the second grading scheme.
4. On average, she sold $48,280 per day.
5. On average, she makes $12.5 per hour.

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To find the weighed average, we multiply each value by it's weight.

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Question 1:

• Grade of 91, with a weight of 67%.
• Grade of 91, with a weight of 33%.

Thus:

$F = 91\times0.67 + 91\times0.33 = 91$

The final grade is 91.

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Question 2:

• Grade of 83, with a weight of 40%(highest grade).
• Grade of 60, with a weight of 30%.
• Grade of 52, with a weight of 30%.

Thus:

$F = 83\times0.4 + 60\times0.3 + 52\times0.3 = 66.8$

The final grade is 66.8.

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Question 3:

With teacher 1:

• 75 with a weight of 25%.
• 80 with a weight of 10%.
• 85 with a weight of 40%.
• 62 with a grade of 25%.

Thus:

$F_1 = 75\times0.25 + 80\times0.1 + 85\times0.4 + 62\times0.25 = 76.25$

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With teacher 2:

• 75 with a weight of 15%.
• 80 with a weight of 10%.
• 85 with a weight of 60%.
• 62 with a weight of 15%.

Thus:

$F_2 = 75\times0.15 + 80\times0.1 + 85\times0.6 + 62\times0.15 = 79.55$

The higher grade would be 79.55, with the second grading scheme.

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Question 4:

• Average of $36,432, with a weight of $\frac{3}{3+10} = \frac{3}{13}$
• Average of $51,834, with a weight of $\frac{10}{13}$

Thus:

$A = 36432\frac{3}{13} + 51834\frac{10}{13} = \frac{36432\times3 + 51834\times10}{13} = 48280$

On average, she sold $48,280 per day.

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Question 5:

• Average of $14.84, with a weight of $\frac{6}{6+8} = \frac{6}{14} = \frac{3}{7}$
• Average of $10.76, with a weight of $\frac{4}{7}$

Thus:

$A = 14.84\frac{3}{7} + 10.76\frac{4}{7} = \frac{14.84\times3 + 10.76\times4}{7} = 12.5$

On average, she makes $12.5 per hour.

A similar problem is given at brainly.com/question/24398353