3 years ago

Which distance did Brook measure?

Mathematics

1 answer:

katovenus [111]3 years ago

3 0

Where’s the rest of the info??

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Answer:

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Step-by-step explains:

(Sorry If I am wrong I just guessed.)

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Fiona wrote the linear equation y = y equals StartFraction 2 over 5 EndFraction x minus 5.x – 5. When Henry wrote his equation,

xeze [42]

Answer:

D. $x-\frac{5}{2}y = \frac{25}{2}$

Step-by-step explanation:

Given

$y = \frac{2}{5}x - 5$

Required

Determine its equivalent

<em>From the list of given options, the correct answer is</em>

$x - \frac{5}{2}y = \frac{25}{2}$

This is shown as follows;

$y = \frac{2}{5}x - 5$

Multiply both sides by $\frac{5}{2}$

$\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)$

Open Bracket

$\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5$

$\frac{5}{2}y = x - \frac{25}{2}$

Subtract x from both sides

$\frac{5}{2}y - x = x -x - \frac{25}{2}$

$\frac{5}{2}y - x = - \frac{25}{2}$

Multiply both sides by -1

$-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1$

$-\frac{5}{2}y + x = \frac{25}{2}$

Reorder

$x-\frac{5}{2}y = \frac{25}{2}$

<em>Hence, the correct option is D</em>

$x-\frac{5}{2}y = \frac{25}{2}$

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