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Alika [10]
4 years ago
11

NEED HELP ASAP: Let ​ f(x)=x2−6x+13 ​ . What is the vertex form of f(x)? What is the minimum value of f(x)? Enter your answers i

n the boxes. Vertex form: f(x)= Minimum value of f(x):

Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
8 0

Answer:

I forgot to change the vertex but it's correct

Step-by-step explanation:

Svetach [21]4 years ago
5 0
The vertex form of  f(x)=ax^2+bx+c
f(x)=a(x-h)^2+k

where: h=\dfrac{-b}{2a};\ k=f(h)

We have:  f(x)=x^2-6x+13\to a=1;\ b=-6;\ c=13

substitute:
h=\dfrac{-(-6)}{2\cdot1}=\dfrac{6}{2}=3\\\\k=f(3)=3^2-6\cdot3+13=9-18+13=4
The vertex form of f(x):
f(x)=(x-3)^2+4
The value of minimum is equal k.
Therefore:  y_{min}=4



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