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lyudmila [28]
4 years ago
13

In the linear equation y = 3x - 4, what is the slope and the y intercept?

Mathematics
1 answer:
attashe74 [19]4 years ago
3 0
The slope is 3 and the y-intercept is -4
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Needs steps to solve the following a^2 + 7ab + 10b^2
jonny [76]
Factor : a^2 + 7ab + 10b^2 

In \ this \ case, a=1, b=7b \ and  \ c=10b^2. 

(a+2b)(a+5b)
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3 years ago
A figure is made from 8 units blocks.Its 3 units tall.What is the maximum length the figure could be?Explain.
Aleksandr-060686 [28]
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6 0
3 years ago
If you can multiply Ax B, then which of the following statements is true about
HACTEHA [7]

To multiply B and A, the number of columns of B must matc the number of rows of A.

<h3>When we can multiply two matrices?</h3>

When we multiply two matrices, A and B, we multiply the rows of matrix A by the columns of matrix B.

Now, the number of elements in a row of a matrix, is equal to the number of columns (and the number of elements in a column is equal to the number of rows).

To multiply BxA:

Then, a row on matrix B must have the same number of elements than a column in row A.

Then, to multiply BxA, the number of columns of B must match the number of rows of A, meaning that the correct option is the last one.

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brainly.com/question/11989522

8 0
2 years ago
Evaluate each expression.
KonstantinChe [14]

Answer:

Please check the explanation.

Step-by-step explanation:

Solving the expressions

7)

given the expression

\left(-7\right)+\:\left(-10\right)\:-\:5\:+2

  • \mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}
  • \mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:
  • \mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a

so

=\left(-7\right)-10-5+2

=-17-5+2

=-22+2

=-20

8)

\left(-9\right)+4+\left(-8\right)-\left(-7\right)

  • \mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}
  • \mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:
  • \mathrm{Apply\:rule\:}+\left(-a\right)\:=\:-a

so

=-5+\left(-8\right)-\left(-7\right)

=-5-8-\left(-7\right)

=-13-\left(-7\right)

=-13+7

=-6

9)

\left(-6\right)\:-\:\left(2\:\times \:4\right)\:-\:\left(-1\right)\:

  • \mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}
  • \mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:\:

so

\left(-6\right)-\left(2\times \:4\right)-\left(-1\right)

Calculate within parentheses

=\left(-6\right)-8-\left(-1\right)

=-14-\left(-1\right)

=-14+1

=-13

10)

\left(-8\right)\:+\:\left(-4\:\div \:-4\right)\:-\:8

solving

\left(-8\right)+\left(-\frac{4}{-4}\right)-8

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=-8-\frac{4}{-4}-8

=-8-\left(-1\right)-8

\mathrm{Apply\:rule}\:-\left(-a\right)=a

=-8+1-8

\mathrm{Add/Subtract\:the\:numbers:}\:-8+1-8=-15

=-15

5 0
3 years ago
Please help answer the question ​
Studentka2010 [4]

Answer:

I am sure that answer is 18.

I hope you got it

6 0
4 years ago
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