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3 years ago

In the linear equation y = 3x - 4, what is the slope and the y intercept?

Mathematics

1 answer:

attashe74 [19]3 years ago

3 0

The slope is 3 and the y-intercept is -4

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Solve the inequality. Graph the solution. Describe the graph in the area provided. Be sure to indicate where there is an open or

natka813 [3]

Step-by-step explanation:

The given inequality is :

$-27\ge \dfrac{1}{2}(6x-12)$

Solving RHS of the inequality:

$-27\ge \dfrac{1}{2}\times 2(3x-6)\\\\-27\ge (3x-6)$

Adding 6 both sides of the inequality

$-27+6\ge (3x-6)+6\\\\-21\ge 3x\\\\x\le -7$

The attached figure shows the graph for the given inequality.

7 0

3 years ago

If you are reading this please help!!!!

Soloha48 [4]

Given:

$1. -3 x^{2}\left(4 x^{3}-7\right)\\$2. $(6 x-5)(2 x+3)$\\3. $(3 x-1)\left(x^{2}+5 x-2\right)$$

To find:

The product of the polynomials.

Solution:

1. $-3 x^{2}\left(4 x^{3}-7\right)$ $=-3 x^{2}(4 x^{3}) -3 x^{2}(-7)$

Multiply the numerical coefficient and add the powers of x.

$=-12 x^{5}+21 x^{2}$

2. $(6 x-5)(2 x+3)=6 x(2 x+3)-5(2x+3)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=12 x^2+18x-10 x-15$

$=12 x^2+8x-15$

3. $(3 x-1)\left(x^{2}+5 x-2\right)=3 x(x^{2}+5 x-2)-1(x^{2}+5 x-2)$

Multiply each term of first polynomial with each term of 2nd polynomial.

Multiply the numerical coefficient and add the powers of x.

$=3x^{3}+15 x^2-6x-x^{2}-5 x+2$

Add or subtract like terms together.

$=3x^{3}+14 x^2-11x+2$

The answer for multiplying polynomials:

$1. -12 x^{5}+21 x^{2}$

$2. \ 12 x^2+8x-15$

$3. \ 3x^{3}+14 x^2-11x+2$

3 0

3 years ago

What do you do when ur bathtub wont work

lubasha [3.4K]

Answer:

Sometimes I l i c k myself like a cat but other times I'll just get orange juice and pour it on myself. Either way works great!

Step-by-step explanation:

8 0

3 years ago

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Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 5 x + 6 = 0 a. x = -3 or x = -2 c. x =

sineoko [7]

Answer:

Step-by-step explanation:

I did it on math class

6 0

3 years ago

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An initial population of 415

slamgirl [31]

Answer:

The exponential function to model the duck population is:

f(n)=415*(1.32)^n, where:

x is the duck population

n is the number of years

Step-by-step explanation:

In order to calculate the duck population you can use the formula to calculate future value:

FV=PV*(1+r)^n

FV=future value

PV=present value

r=rate

n=number of periods of time

In this case, the present value is the initial population of 415 and the rate is 32%. You can replace these values on the formula and the exponential function to model the duck population would be:

f(n)=415*(1+0.32)^n

f(n)=415*(1.32)^n, where:

x is the duck population

n is the number of years

3 0

3 years ago