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3 years ago

5

How much would a sales discount be on an invoice that totals 3,000, is dated January 14th, has terms of 2/10bnet30, and is paid

on January 25th?

1 answer:

MrMuchimi3 years ago

8 0

I think your answer is 60 sorry if its wrong
(^>^) <span />

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Can someone help please

s344n2d4d5 [400]

Okay, so this is exponential. The formula for the exponental function is Y=ab^x

a is the y-intercept

b is the rate/ratio

x is the time

According to the graph, (remember the y-intercept is in the y-axis) so 2 is the y-intercept.

Knowing what the y-intercept is, you know what the answer is.

A.

5 0

3 years ago

Serena and Sienna both work for a company that pays 12 dollars per hour for the first 40 hours of work in a week. If an employee

Free_Kalibri [48]

Answer:

87 total hours.

Step-by-step explanation:

The equation 456/12 Gives you how many hours Sienna worked. (38)

642-480 will give you how much money Serena made off of Just OT (162)

162/18 = 9 (9 is how many overtime hours Serena worked.)

Serena worked her normal 40 hours, then worked over time, so you have to add 40 to the equation.

9+40+38 = 87

Serena and Sienna worked 87 total hours.

7 0

3 years ago

What is the answer to this

Novay_Z [31]

The answer is zero.

7 0

3 years ago

2. Flying to Kampala with a tailwind a plane averaged 158 km/h . On the return trip the plane only averaged 112 km/h while flyin

stiv31 [10]

Answer:

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

Step-by-step explanation:

Given that:

Speed of plane with the wind = 158km/h

Speed of plane against the wind = 112km/h

Let,

x be the speed of plane

y be the speed of wind

According to given statement;

x+y = 158 Eqn 1

x-y = 112 Eqn 2

Adding Eqn 1 and 2

$x+y+x-y=158+112\\2x = 170\\\frac{2x}{2}=\frac{270}{2}\\x=135$

Putting x = 135 in Eqn 1

135+y = 158

y = 158-135

y = 23

Hence,

Speed of plane in still air = 135 km/h

Speed of wind = 23 km/h

8 0

3 years ago

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago