This can be solved a couple of ways. One way is to use the Pythagorean theorem to write equations for the magnitude from the components of the forces. That is what was done in the graph here.
Another way is to use the Law of Cosines, which lets you make direct use of the angle between the vectors.
.. 13 = a^2 +b^2 -2ab*cos(90°)
.. 19 = a^2 +b^2 -2ab*cos(120°)
Subtracting the first equation from the second, we have
.. 6 = -2ab*cos(120°)
.. ab = 6
Substituting this into the first equation, we have
.. 13 = a^2 +(6/a)^2
.. a^4 -13a^2 +36 = 0
.. (a^2 -9)(a^2 -4) = 0
.. a = ±3 or ±2
The magnitudes of the two forces are 2N and 3N, in no particular order.
Hope it helps 10 mins on the elliptical and 12 on the treadmil
Answer:
Step-by-step explanation:
f(x) = x + 2.....change f(x) to y
y = x + 2....now switch x and y and solve for y
x = y + 2
x - 2 = y....change y to f-1(x)...represents an inverse
f-1(x) = x - 2 <== ur inverse
Answer:
A) slope = 2, y-intercept = -6
B) slope = -4, y-intercept = 6
Step-by-step explanation:
A) y = 2x - 6
The equation for a line is y = mx + b, where <em>m</em> represents the slope, and <em>b</em> represents the y-intercept. So, to find the slope and y-intercept, all we have to do is look at the line's equation.
Here, the <em>m </em>is 2, so the slope is 2
The <em>b</em> is -6, so the y-intercept is -6
B) y = -4x + 6
Here, the <em>m</em> is -4, so the slope is -4
The <em>b </em>is 6, so the slope is 6
You would graph the equation y = 4x + 6 by plotting a point at the y-intercept of the line, which would be 6. Then, for every time you move one space to the right, you'd plot a point four spaces up to show the slope of four.