WHO WANTS BRAINLIEST ANSWER!!!!!! PLZ HELP ME RN!!!! I NEED HELP ASAP!!!!!!!!

OF Bisects EOG. M EOF = y+ 30 and M FOG = 3y - 50. Solve for y

Nataly_w [17]

Since it says that OF bisects EOG, it means that the angles on either side have the same measure (i.e. EOF = FOG).

We can use this to solve by setting the expressions equal to each other and solving for y.

y+30=3y-50
2y=80
y=40

6 0

3 years ago

Give the first three non-zero terms of the Taylor series for f(x) = tan(x) about x 0· Use this to approximate tan(1) and give an

alexdok [17]

Answer:

$f(x)=x+\dfrac{x^{3}}{3}+\dfrac{2x^{4}}{3}....$

Approximate error = 0.4426

Step-by-step explanation:

f(x)=tanx, a=0

Maclaurin series formula used is given below

$f(x)=\sum_{n=0}^{\infty}\dfrac{f^{(n)}(0)x^{n}}{n!}=f(0)+f'(0)x+\dfrac{f''(0)}{2!}x^{2}+\dfrac{f'''(0)}{3!}x^{3}+....$

f(x)=tanx

f(0)=tan0=0

$f'(x)=sec^{2}x\\f'(0)=sec^{2}0=1\\f''(x)=2sec^{2}xtanx\\f''(0)=2sec^{2}0tan0=0\\f'''(x)=-4sec^{2}x+6sec^{4}x\\f'''(0)=-4sec^{2}0+6sec^{4}0=-4+6=2\\$

$f''''(x)=-8(2sec^{2}xtan^{2}x+sec^{4}x)+24(4sec^{4}xtan^{2}x)+sec^{6})\\f''''(0)=-8(0+1)+24(0+1)=-8+24=16\\$

$f(x)=0+x+0+\dfrac{2x^{3}}{3!}+\dfrac{16x^{4}}{4!}\\$

$f(x)=x+\dfrac{x^{3}}{3}+\dfrac{2x^{4}}{3}\\$

Hence, the Taylor series for f(x)=tanx is given by

$f(x)=x+\dfrac{x^{3}}{3}+\dfrac{2x^{4}}{3}....$

Maclaurin series upper bound error formula used is given as

R_n(x)=|f(x)-T_n(x)|

R_3(x)=|tanx-T_3(x)|

$R_3(x)=|tanx-x-\dfrac{x^{3}}{3}-\dfrac{2x^{4}}{3}|$

Plugging this value x=1

$R_3(x)=|tan(1)-1-\dfrac{1}{3}-\dfrac{2}{3}|\\$

R_3(x)=|1.5574-1-0.333-0.666|

R_3(x)=|-0.4426|=0.4426

Hence, upper bound on the error approximation

tan(1)=0.4426

6 0

3 years ago

PLEASE HELP!<br> F.11<br> G.12<br> H.22<br> J.24

Natasha_Volkova [10]

Answer:

G. 12

Step-by-step explanation:

5/10=(x+5)/(3x+3)

1/2=(x+5)/(3x+3)

Cross multiply

3x+3=2x+10

x=7

AC=x+5=12

4 0

3 years ago

Read 2 more answers

A circle is defined by x^2+y^2+2gx+2fy-15=0. The gradient of the tangent to the circle at the point (3,2) is -1/2. Find the valu

natita [175]

Answer:

(g, f) = (-1, 2)

Step-by-step explanation:

The equation can be put into standard form:

(x^2 +2gx) +(y^2 +2fy) = 15

(x^2 +2gx +g^2) +(y^2 +2fy +f^2) = 15 +g^2 +f^2

(x +g)^2 +(y +f)^2 = 15 +g^2 +f^2 . . . . equation in standard form

The point (3, 2) is on the circle, so one of the equations we have is ...

(3+g)^2 +(2 +f)^2 = 15 +g^2 +f^2

9 +6g +g^2 +4 +4f +f^2 = 15 +g^2 +f^2

6g +4f = 2 . . . . . . . subtract g^2 +f^2 +13

3g +2f = 1 . . . . . . . divide by 2

__

A line through the center of the circle is perpendicular to the tangent at the point of tangency. That line will have a slope that is the negative reciprocal of the tangent's slope: m = -1/(-1/2) = 2. Then in point-slope form the equation of the line through the center is ...

y -2 = 2(x -3)

2x -y = 4 . . . . rearrange to standard form

The point at the center of the circle, (-g, -f), satisfies this equation, so we have another relation for f and g:

2(-g) -(-f) = 4

2g -f = -4 . . . . . . multiply by -1

Adding twice this equation to the one above, we have ...

2(2g -f) +(3g +2f) = 2(-4) +(1)

7g = -7 . . . . . . . . . simplify

g = -1 . . . . . . . . . . divide by 7

f = 2g +4 = 2(-1) +4 = 2 . . . find the corresponding value of f

The values of f and g are: f = 2 and g = -1.

7 0

3 years ago

The equation x + y = z relates the whole numbers x, y, and z. How does z compare to x? Y is z less than x. Y is z more than x. X

rewona [7]

Answer:

x is y less than z

Step-by-step explanation:

The given equation is x + y = z

This equation relates the whole numbers x, y, and z.

This equation can be rearranged to make x the subject of the formula or to make y the subject of the formula. When this is done, the relationship between the terms or numbers would be clearly expressed.

Making y the subject of the formula, it becomes

y = z-x (this shows that z is greater than y by x)

Making x the subject of the formula, it becomes

x = z-y (this shows that z is greater than x by y)

Looking at the options given, the correct comparisons between z and x is

x is y less than z

7 0

3 years ago