Call (F) the age of the father and (J) the age of Julio
The F & J are related in this way: F=4J
Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.
Algebraically that is: F + J ≥ 55
You can substitute F with 4J to find the solution for J:
4J + J ≥ 55
5J ≥ 55
Now divide both sides by 5
5J/5 ≥ 55/5
J ≥ 11
That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
I would help you but I don’t know
Step-by-step explanation:
Answer:
Step-by-step explanation: Need to work out your scale factor which is 1.5.
8 * 1.5 = 12
CE = 12
12 * 9 = 108/2 = 59 that is the area of triangle ACE
8 * 6 = 48/2 = 24 that is the area of triangle BCD
ACE - BCD = ABDE
59 - 24 = 35cm^2
Answer:

Step-by-step explanation:
let x be the numerator of the rational number then 2x is the denominator
original fraction = 
subtracting 3 from numerator and adding 7 to denominator , gives
=
( cross- multiply )
5(x - 3) = 2(2x + 7) ← distribute parenthesis on both sides )
5x - 15 = 4x + 14 ( subtract 4x from both sides )
x - 15 = 14 ( add 15 to both sides )
x = 29
rational number = 
Answer:
The answer to your question is:
Fraction he has review = 17/36
Fraction he have to study = 19/36
Step-by-step explanation:
Data
Monday studied = 2/9
Tuesday = 1/4
Fraction he has review = ?
Fraction he has left = ?
Process
As the denominator is 9, consider the whole is 9.
Then: Fraction left on Monday = 9/9 - 2/9
= 7 / 9
Fraction left on Tuesday = 7/9 - 1/4
= (28 - 9) / 36
= 19 / 36
Fraction he has review = 17/36
Fraction he have to study = 19/36