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3 years ago

HELPPPP MEE PLEASEEE!!

Mathematics

2 answers:

ankoles [38]3 years ago

7 0

Answer:

6 , 1

5 , 2

4 , 3

Step-by-step explanation:

Just swap the numbers.

ruslelena [56]3 years ago

6 0

Answer:

x (input) y (output)

6 1

5 2

4 3

3 4

Step-by-step explanation:

Because it is the <em>inverse</em> of the red table, the blue table would be the opposite: (Answers are shown above)

I hope this helps :)

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kipiarov [429]

I had this question on my test>>>>>>>>> v=5y+22

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6 0

3 years ago

Write 0.5 as a percentage

maw [93]

Answer:

50%

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the differential coefficient of <br><img src="https://tex.z-dn.net/?f=e%5E%7B2x%7D%281%2BLnx%29" id="TexFormula1" title="e^

Gemiola [76]

Answer:

$\rm \displaystyle y' = 2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x}$

Step-by-step explanation:

we would like to figure out the differential coefficient of $e^{2x}(1+\ln(x))$

remember that,

the differential coefficient of a function y is what is now called its derivative y', therefore let,

$\displaystyle y = {e}^{2x} \cdot (1 + \ln(x) )$

to do so distribute:

$\displaystyle y = {e}^{2x} + \ln(x) \cdot {e}^{2x}$

take derivative in both sides which yields:

$\displaystyle y' = \frac{d}{dx} ( {e}^{2x} + \ln(x) \cdot {e}^{2x} )$

by sum derivation rule we acquire:

$\rm \displaystyle y' = \frac{d}{dx} {e}^{2x} + \frac{d}{dx} \ln(x) \cdot {e}^{2x}$

Part-A: differentiating $e^{2x}$

$\displaystyle \frac{d}{dx} {e}^{2x}$

the rule of composite function derivation is given by:

$\rm\displaystyle \frac{d}{dx} f(g(x)) = \frac{d}{dg} f(g(x)) \times \frac{d}{dx} g(x)$

so let g(x) [2x] be u and transform it:

$\displaystyle \frac{d}{du} {e}^{u} \cdot \frac{d}{dx} 2x$

differentiate:

$\displaystyle {e}^{u} \cdot 2$

substitute back:

$\displaystyle \boxed{2{e}^{2x} }$

Part-B: differentiating ln(x)•e^2x

Product rule of differentiating is given by:

$\displaystyle \frac{d}{dx} f(x) \cdot g(x) = f'(x)g(x) + f(x)g'(x)$

let

$f(x) \implies \ln(x)$
$g(x) \implies {e}^{2x}$

substitute

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \frac{d}{dx}( \ln(x) ) {e}^{2x} + \ln(x) \frac{d}{dx} {e}^{2x}$

differentiate:

$\rm\displaystyle \frac{d}{dx} \ln(x) \cdot {e}^{2x} = \boxed{\frac{1}{x} {e}^{2x} + 2\ln(x) {e}^{2x} }$

Final part:

substitute what we got:

$\rm \displaystyle y' = \boxed{2 {e}^{2x} + \frac{1}{x} {e}^{2x} + 2 \ln(x) {e}^{2x} }$

and we're done!

6 0

3 years ago

ATCE Learning Center wants to make a net profit of $650,000 on the manual it sells to schools. The fixed costs for producing the

Elanso [62]

We are to solve for the price per unit. Let "x" be the price per unit.
The given values are the following:
Variable Cost = 1250,000 *x
Fixed Cost = $780,000
Net Profit = $650,000
Variable cost per unit = $19.85

The solution is shown below:
$650,000 = 1,250,000*x - $780,000 - $1,250,000*$19.85
x = $26, 242, 500 / 1,250,000 units
x = $20.994

The price per unit is $20.99 and the answer is letter "D".

6 0

3 years ago

Write the subtraction expression as an equivalent addition expression and then evaluate it.

Harrizon [31]

Answer:

Step-by-step explanation:

Given the expression -3-(-5)

This is also expressed as;

-3(-5)

= -3 + 5 (The product of two negative sign gives a positive sign)

= 5 - 3

= 2

Hence the result of the expression is 2

6 0

3 years ago