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3 years ago

7

A snack stand offers 6 choices of sandwiches and 3 choices of beverages. How many combinations of 1 sandwich and 1 beverage are

possible?

1 answer:

Strike441 [17]3 years ago

5 0

Answer:

<h2>18</h2><h2 />

Step-by-step explanation:

It offers 6 choices of sandwiches and for each choice (among these 6) 3 choices of beverages

then

the number of possible combinations of 1 sandwich and 1 beverage is :

6×3 = 18

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ehidna [41]

Answer:

25.047 or roughly 25.

Step-by-step explanation:

I solved it wrong the first time then i double check with wolframalpha and got the correct number.

We know that the area of the tile is 18 $\sqrt{3}$ and it makes a triangle, we also know the base and height. In this case the base is 2 $\sqrt{3}^{x/12}$ and the height is also given which is $\sqrt{3}^{\frac{x}{6} }$ .

Area of triangle = $\frac{bh}{2}$ ,

substituting we will end up with 18 $\sqrt{3}$ =( 2 $\sqrt{3}^{x/12}$ * $\sqrt{3}^{\frac{x}{6} }$ ) / 2

Here is the tricky part $\sqrt{x} = x^{\frac{1}{2} }$ , i totally forgot about that lol.

Simplifying: we will get 18 $\sqrt{3}$ = $3^{\frac{x}{8} }$

Now, in order to find the x, we will need to take the log of both sides.

$log18\sqrt{3} = \frac{x}{8} log3$

Solving for x we end up getting:

$8\frac{log18\sqrt{3} }{log3}$ = x

where x = 25.047.

To be honest I deserve a nobel prize not a brainliest lol.

Good question bro, take it easy.

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