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marshall27 [118]
3 years ago
10

M<1 =40-4x; and m<2=50-8x

Mathematics
1 answer:
matrenka [14]3 years ago
6 0
What's the question?
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Ethan's grade on course I tests were 90
Svetlanka [38]

The mode of his grade is 90 because it is the number most frequented

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3 years ago
a map shows the town where niko lives. the actual distance from niko's house to his school is 3miles, and measures one-half inch
garri49 [273]

6 miles = 1in

9 miles = 1 1/2in

12 miles = 2in

and it goes on, hope this helps!

6 0
3 years ago
Read 2 more answers
Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
Dana invests £5000 for 4 years in a savings account She gets 2% per annum compound interest in the first year, then x% for 3 yea
Vanyuwa [196]

Answer:

£1,330.46

Hope this helps, mate!

Step-by-step explanation:

Hope this helps, mate! :)

6 0
2 years ago
X = (y + 3) / 12 solve for y
slega [8]

Answer:

y = 12x-3

Step-by-step explanation:

X = (y + 3) / 12

Multiply each side by 12 to clear the fraction

12 x = (y+3)/12 *12

12x = y+3

Subtract 3 from each side

12x -3 = y+3-3

12x-3 =y

8 0
4 years ago
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