Answer:
D I believe
Step-by-step explanation:
Answer:
(a)
Distance from player should be 13.82 feet or 36.2 feet
(b)
The ball will go over the net
Step-by-step explanation:
we are given
The ball follows a path given by the equation
![y=-0.01x^2+0.5x+3](https://tex.z-dn.net/?f=y%3D-0.01x%5E2%2B0.5x%2B3)
where
x and y are measured in feet and the origin is on the court directly below where the player hits the ball
(a)
net height is 8 ft
so, we can set y=8
and then we can solve for x
![8=-0.01x^2+0.5x+3](https://tex.z-dn.net/?f=8%3D-0.01x%5E2%2B0.5x%2B3)
![8\cdot \:100=-0.01x^2\cdot \:100+0.5x\cdot \:100+3\cdot \:100](https://tex.z-dn.net/?f=8%5Ccdot%20%5C%3A100%3D-0.01x%5E2%5Ccdot%20%5C%3A100%2B0.5x%5Ccdot%20%5C%3A100%2B3%5Ccdot%20%5C%3A100)
![800=-x^2+50x+300](https://tex.z-dn.net/?f=800%3D-x%5E2%2B50x%2B300)
![-x^2+50x-500=0](https://tex.z-dn.net/?f=-x%5E2%2B50x-500%3D0)
![x^2-50x+500=0](https://tex.z-dn.net/?f=x%5E2-50x%2B500%3D0)
we can use quadratic formula
![x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%20%5Csqrt%7Bb%5E2-4ac%7D%7D%7B2a%7D)
![x=\frac{-50\pm \sqrt{50^2-4\left(-1\right)\left(-500\right)}}{2\left(-1\right)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-50%5Cpm%20%5Csqrt%7B50%5E2-4%5Cleft%28-1%5Cright%29%5Cleft%28-500%5Cright%29%7D%7D%7B2%5Cleft%28-1%5Cright%29%7D)
![x=5\left(5-\sqrt{5}\right),\:x=5\left(5+\sqrt{5}\right)](https://tex.z-dn.net/?f=x%3D5%5Cleft%285-%5Csqrt%7B5%7D%5Cright%29%2C%5C%3Ax%3D5%5Cleft%285%2B%5Csqrt%7B5%7D%5Cright%29)
![x=13.82,x=36.2](https://tex.z-dn.net/?f=x%3D13.82%2Cx%3D36.2)
So, distance from player should be 13.82 feet or 36.2 feet
(b)
we can plug x=30 and check whether y=8 ft
![y=-0.01(30)^2+0.5(30)+3](https://tex.z-dn.net/?f=y%3D-0.01%2830%29%5E2%2B0.5%2830%29%2B3)
![y=9ft](https://tex.z-dn.net/?f=y%3D9ft)
we know that
height of net is 8 ft
so, the ball will go over the net
If you can't see the picture the answer is: (y+4)(y+2).
Hope this helps, and May the Force Be With You!
-Jabba
Answer:
$20,000
Step-by-step explanation:
You can quickly figure this by recognizing that the difference in commission must be the same as the base salary:
2.5%(car price) = $500
car price = $500/0.025 = $20,000
__
If you prefer, you can get there with equations.
At Job 1, the pay is ...
y = 10%×(car price)
At Job 2, the pay is ...
y = 7.5%×(car price)
Setting the equal (the two opportunities pay the same), we have ...
0.10(car price) = 500 +0.075(car price)
0.025(car price) = 500 . . . . . . . . subtract 0.075(car price)
car price = 500/0.025 = 20,000 . . . . divide by 0.025
Jim would have to sell a $20,000 car each week for the jobs to pay the same.
Answer:
e,q,u,a,t,i,n & EQUATIONYL
Step-by-step explanation:
K∩L:
First write both the words, equation and inequality down.
E Q U A T I O N
I N E Q U A L I T Y
You can see EQUATIN repeats in both of the words.
K∪L:
First write both the words, equation and inequality down.
E Q U A T I O N
I N E Q U A L I T Y
This time just write down all the letters EXCEPT the ones that repeat. EQUATIONYL