Let's solve your equation step by step
-8=3-5(x+6)
Step 1: simplify both sides of the equation
-8=3-5(x+6)
-8=3+(-5)(x)+(-5(6) (distribute)
-8=3+-5x+-30
-8=(-5x)+(3+-30) (combine like terms)
-8=-5x+-27
-8=-5x-27
Step 2: flip the equation
-5x-27=-8
Step 3: add 27 to both sides
-5x-27+27=-8+27
-5x=19
Step 4: Divide both sides by -5
-5x/-5 = 19/-5
Answer : x= -19/5
Sense we are wanting to find <u>
how many were miss</u>
, then, we are practically going to subtract the following:
![\boxed{76-100}= \ \left[\begin{array}{ccc}\bf{24\end{array}\right]](https://tex.z-dn.net/?f=%5Cboxed%7B76-100%7D%3D%20%5C%20%20%20%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cbf%7B24%5Cend%7Barray%7D%5Cright%5D%20)
So, from this begin understood, we would then combine both the penalties that were shotted, to the onces that weren't.
So, b subtracting these both, we would grab the result, and then smash that with the number of the penalties that were made in.
Your answer:
i believe it would be: 1/2y = x
y = 2.5
Answer:
volume of cube share box = 67.92 inch²
Step-by-step explanation:
given data
soccer ball volume = 85.3π cubic inches
solution
we know that ball will fit inside the box when box length will be equal to diameter of ball
and here soccer ball volume will be express as
soccer ball volume =
.................1
85.3π =
solve it we get
r³ = 69.9765
r = 4.12 inch
so diameter = 2 × 4.12 = 8.24 inch
diameter = length of box side
volume of cube share box = a²
volume of cube share box = 8.24²
volume of cube share box = 67.92 inch²
<u>Answer</u>

<u>Detailed Explanation </u>
To simply answer this, since .189 has three digits we are going to be inserting 999 as the denominator since it is a repeating decimal.

We could simplify the answer!

Therefore, the answer would simply be 

<u>Always Remember </u>
In the future, always remember whenever you have a three digit decimal and the problem asks you to convert it into a fraction, you should always insert 1000 as the denominator (the numerator is basically the decimal without the decimal point) and simplify if necessary.