All categories

2 years ago

Why is a scatterplot an appropriate display for this data set?

Mathematics

2 answers:

Nookie1986 [14]2 years ago

5 0

Answer:

It could be because it shows trends and shows outliers and all the data in a way that makes sense

Step-by-step explanation:

sp2606 [1]2 years ago

4 0

Answer:

A scatter plot can also be useful for identifying other patterns in data. We can divide data points into groups based on how closely sets of points cluster together. Scatter plots can also show if there are any unexpected gaps in the data and if there are any outlier points

pls mark as brainliest answer

Step-by-step explanation:

You might be interested in

Nind reeds

Usimov [2.4K]

Answer:

42 gallons.

Step-by-step explanation:

count every inch *2 and calculate gallons

3 0

2 years ago

Convert the rectangular equation to polar form. assume a is less than 0.<br> x=10

Ilia_Sergeevich [38]

R cos(t) =10 r = 10/cos(t)

5 0

3 years ago

Lorelle pays someone $35 to clear her driveway when it snows. She wants to buy an electric snow blower for $689 so that she can

Ad libitum [116K]

Since 689 / 35 is about 20, it would take around 4 seasons to break even

3 0

3 years ago

Read 2 more answers

Find the measure of the exterior angle shown

RUDIKE [14]

Answer:

• exterior angle of a triangle is equal to sum of opposite interior angle

(6x-7) = (103-x) + 2x

6x-7 = 103 - x + 2x

6x-7 = 103 + x

6x - 7 - x -103 = 0

6x - x - 110 = 0

5x - 110 = 0

5x = 110

x = 110/5

x = 22

as exterior angle is (6x-7)

= 6 × 22 - 7

= 125

-> Exterior angle is 125°

pls do mark as brainliest. . . ☺

5 0

3 years ago

A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will

enyata [817]

Answer:

a) Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

$H_{0}$ : mu=183 days

$H_{a}$ : mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

4 0

3 years ago