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3 years ago

Why is a scatterplot an appropriate display for this data set?

Mathematics

2 answers:

Nookie1986 [14]3 years ago

5 0

Answer:

It could be because it shows trends and shows outliers and all the data in a way that makes sense

Step-by-step explanation:

sp2606 [1]3 years ago

4 0

Answer:

A scatter plot can also be useful for identifying other patterns in data. We can divide data points into groups based on how closely sets of points cluster together. Scatter plots can also show if there are any unexpected gaps in the data and if there are any outlier points

pls mark as brainliest answer

Step-by-step explanation:

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What is 439 over 937 in simplest form

Licemer1 [7]

I do believe it is 0.46852

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3 years ago

PLEASE HELP QUICKLY!!! A student's parents offer him one of two options to receive scholarship money for college.

emmainna [20.7K]

Answer:

A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more

Step-by-step explanation:

Option A Versus Option B

Option A Option B

Day Amount Deposited Day Amount Deposited

0 $40,000.00 0 $1.00

1 $40,250.00 1 $2.00

2 $40,500.00 2 $4.00

...

30 $47,500 16 $65,536.00

Answer:

A = $47,500.00, B = $65,536.00; B, because he receives $18,036.00 more

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3 years ago

G(4) =????<br> Can Someone please help Me on this question

melomori [17]

Answer:

when x=4, the value of y is the answer.

when x=4,we can see that the value of y is 1

8 0

3 years ago

Please help me on this question

s2008m [1.1K]

It’s d 30% I believe

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3 years ago

At a carnival, contestants are asked to keep rolling a pair of dice until they roll snake eyes. The number of rolls needed has a

Stells [14]

Answer:

The two numbers of rolls are 25.2 and 46.8.

Step-by-step explanation:

The Chebyshev's theorem states that, if X is a r.v. with mean µ and standard deviation σ, then for any positive number k, we have

$P (|X -\mu| < k\sigma) \geq (1-\frac{1}{k^{2}})$

Here

$(1-\frac{1}{k^{2}})=0.75\\\\\Rightarrow \frac{1}{k^{2}}=0.25\\\\\Rightarrow k=\sqrt{\frac{1}{0.25}}\\\\\Rightarrow k=2$

Then we know that,

$|X - \mu| \geq k\sigma,\\\\ \Rightarrow \mu - k\sigma \leq X \leq \mu + k\sigma$ .

Here it is given that mean (µ) = 36 and standard deviation (σ) = 5.4.

Compute the two values between which at least 75% of the contestants lie as follows:

$P(\mu - k\sigma \leq X \leq \mu + k\sigma)=0.75\\\\P(36 - 2\cdot\ 5.4 \leq X \leq 36 + 2\cdot\ 5.4)=0.75\\\\P(25.2\leq X\leq 46.8)=0.75$

Thus, the two numbers of rolls are 25.2 and 46.8.

8 0

3 years ago