Because it is extremely hard to find the area of this figure all together, it would be in our best interest to split this figure up into three different pieces: the two horizontal rectangles, and the verticle rectangle. We can find the area of all three and add them up. Be aware that there are two different ways that you can break this figure up, As shown in the attachments. I will be using the first image (the one with the tall horizontal rectangles, NOT the almost-squares).
So, we see that we have enough information to solve for the area of the left-most rectangle. Area = lw. 10 x 4 = 40, so the area is 40. Next, we have to notice, that the horizontal rectangles are also the same, so both of the areas of the two horizontal rectangles are 40.
Now, we can find the middle rectangle. We know that the length of the entire thing is 18, but it is taken up by 8 (4+4) of the horizontal triangles, so 18-8=10, so the length Is 10. We also know that the height of the horizontal rectangles is 10, so 10-3=7. Our dimensions for the rectangle are 10x7 or 70 square units. If we add them all together, 40+40+70=150.
The area is 150 square units
Answer:
5 - 3i.
Step-by-step explanation:
2 + 4i + 3 - 7i Bring like terms together:
= 2 + 3 + 4i - 71
= 5 - 3i.
X = -3, y = 2 rise over run
Answer:
x = 10.3
Step-by-step explanation:
x + 24. 5 = 34.8
- 24.5 - 24.5
x = 10.3
Check your answer:
x + 24. 5 = 34.8
10.3 + 24.5 = 34.8
34.8 = 34.8
Hope this helps!
Answer:

Step-by-step explanation:
step 1
we have the points
(-1,0), (-2,0), and (0,2)
Plot the points
using a graphing tool
see the attached figure
The graph of a quadratic function must be a vertical parabola open upward
The vertex is a minimum
The quadratic function in general form is equal to

Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c
(0,2)
For x=0, y=2
substitute

(-1,0)
For x=-1, y=0
substitute

---->
----> equation A
(-2,0)
For x=-2, y=0
substitute

----> equation B
we have the system
----> equation A
----> equation B
substitute equation A in equation B
solve for b

Find the value of a
therefore
The quadratic function in general form is equal to

see the attached figure N 2 to better understand the problem