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Kobotan [32]
3 years ago
7

A software designer is mapping the streets for a new racing game. All of the streets are depicted as either perpendicular or par

allel lines. The equation of the lane passing through A and B is -7x + 3y = -21.5. What is the equation of the central street PQ?
A. -3x + 4y = 3
B.-1.5x − 3.5y = -31.5
C.2x + y = 20
D.-2.25x + y = -9.75

Mathematics
2 answers:
jarptica [38.1K]3 years ago
8 0

Answer:

Option B is correct .i.e., -1.5x - 3.5y = -31.5

Step-by-step explanation:

Given: All streets are either parallel or perpendicular.

            Equation of Street AB , -7x + 3y = 21.5

To find Equation of Street PQ

Re write the given equation in form of slope and intercept form

we get,

3y=7x+21.5

y=\frac{7}{3}+\frac{21.5}{3}

From this slope of street AB is [tex\frac{7}{3}[/tex].

From given pic Street PQ is perpendicular to street AB.

we know that product of slope of perpendicular lines should be equal to -1

let slope of PQ = m

\frac{7}{3}\times m=-1

m=\frac{-3}{7}

Slope of line in Option A).

4y=3x+3

y=\frac{3}{4}+\frac{3}{4}

Slope = \frac{3}{4}

So, this is not required equation.

Slope of line in Option B).

-3.5y=1.5x-31.5

y=\frac{1.5}{-3.5}+\frac{31.5}{3.5}

Slope = \frac{1.5}{-3.5}=\frac{3}{7}

So, this is required equation.

Therefore, Option B is correct .i.e., -1.5x - 3.5y = -31.5

Marat540 [252]3 years ago
4 0
<span>-1.5x − 3.5y = -31.5</span>
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