D.) The mean will increase
The mean is all the numbers added together than divided by the amount of numbers there, so if you do this: 4 + 6 = 10 + 16 = 26 + 15 = 41/5 = 8.2
4 + 6 = 10 + 16 = 26 + 15 = 41 + 23 = 64/6 = 10.66666666666
As you can see it increased! Hope this helped! Pls give brainiest if you can
You do the same as with number you take out the largest allowed amount. For example for 8 you could take out x^2 and y^2 along with the normal factors, So once you factor everything out you would be left with 27x^2y^2(y^3-3x)
Sum f(k)=4k-10 for k=1 to 18.
We sum each term separately and add the sums.
![\sum_1^{18}4k=4\sum_1^{18}k=4[18(1+18)/2]=4*9*19=684](https://tex.z-dn.net/?f=%5Csum_1%5E%7B18%7D4k%3D4%5Csum_1%5E%7B18%7Dk%3D4%5B18%281%2B18%29%2F2%5D%3D4%2A9%2A19%3D684)
Therefore the required sum is 684-180=504
Answer: There are 3 terms
Step-by-step explanation: You count the abcd as 1 term because it is all multiplied together, the e term is counted as another term, so there are 2 terms, and the n2 term is counted as a term getting you 3 terms in total.
Inversely proportional: z = k/r
k = 32 * 1.5 = 48
Plug that into equation
8 = 48/r
Multiply both sides by r
8r = 48
Divide by 8
r = 6
