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3 years ago

A submarine was situated 800 feet below sea level. If it ascends 350 feet,

Mathematics

1 answer:

Lesechka [4]3 years ago

4 0

Answer:

450 feet below sea level

Step-by-step explanation:

<em>ascend = move up = add</em>

<em>800 ft below sea level = -800</em>

-800 + 350 = -450

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The measure of angle BFE is 120°. Find M angle EFD.

Varvara68 [4.7K]

120 + 120 + X + X = 360
240 + 2X = 360
2X = 120
X = 60

6 0

3 years ago

Cube-shaped blocks are packed into a cube-shaped storage container. The edge length of the storage container is 212 feet. The

igor_vitrenko [27]

Answer:

The volume of cube-shaped block is 0.125 cubic feet.

Step-by-step explanation:

We are given the following in the question:

Edge length of storage container =

$2\dfrac{1}{2}\text{ feet}$

Edge length of block =

$\dfrac{1}{5}\times \text{Edge length of container}$

Putting value we get,

Edge length of block =

$\dfrac{1}{5}\times 2\dfrac{1}{2}\\\\=\dfrac{1}{5}\times \dfrac{5}{2}\\\\=\dfrac{1}{2}\text{ feet}$

Volume of cube-shaped block = Volume of cube

$V = \text{(Edge)}^3\\\\V =(\dfrac{1}{2})^3\\\\V = \dfrac{1}{8}\text{ cubic feet}\\\\V = 0.125\text{ cubic feet}$

Thus, the volume of cube-shaped block is 0.125 cubic feet.

7 0

2 years ago

I need to know what the measure of mkl is

LUCKY_DIMON [66]

I would say the answer would be 105

5 0

3 years ago

issac opens his bank account with $500. he deposits $40 each month? write a function that shows the amount in isaacs account aft

bearhunter [10]

500-40x7 soooo your answer would be 220

4 0

2 years ago

Read 2 more answers

If J is the centroid of cde, de=52, fc=15, he=14, find each missing measure

const2013 [10]

Answer:

$DG = 26$

$GE = 26$

$DF = 15$

$CH = 14$

$CE = 28$

Step-by-step explanation:

The figure has been attached, to complement the question.

$DE = 52$

$FC = 15$

$HE = 14$

Given that J is the centroid, it means that J divides sides CD, DE and CE into two equal parts respectively and as such the following relationship exist:

$DF = FC$

$CH = HE$

$DG = GE$

Solving (a): DG

If $DG = GE$ , then

$DE = DG + GE$

$DE = DG + DG$

$DE = 2DG$

Make DG the subject

$DG = \frac{1}{2}DE$

Substitute 52 for DE

$DG = \frac{1}{2} * 52$

$DG = 26$

Solving (b): GE

If $DG = GE$ , then

$GE = DG$

$GE = 26$

Solving (c): DF

$DF = FC$

So:

$DF = 15$

Solving (d): CH

$CH = HE$

$CH = 14$

Solving (e): CE

If $CH = HE$ , then

$CE = CH + HE$

$CE = 14 + 14$

$CE = 28$

7 0

3 years ago