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andre [41]
4 years ago
15

Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) f

rom the nest is (12,5) The second duckling's displacement is (13,-8) How much farther did the second duckling wander than the first duckling?
Mathematics
1 answer:
aksik [14]4 years ago
4 0

the second duckling is wandering by 2.6 units distance than the first duckling .

<u>Step-by-step explanation:</u>

Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:

Let a = (12,5) and b =(13,-8)

The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :

⇒ D  = |b|-|a|

⇒ D  = \sqrt{13^2+(-8)^2} -\sqrt{12^2+5^2}

⇒ D  = \sqrt{233} -\sqrt{169}

⇒ D  =15.26 -13

⇒ D  =2.6

Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .

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Let (x_{1},y_{1}) and  (x_{2},y_{2}) be the two given points  (-20,5) and (-36, 9) respectively.

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