$\frac{ { - 155}^{4} }{ {19}^{2} } \div { (\frac{155}{19} }) ^{3} = \\ \frac{ { - 155}^{4} }{{19}^{2} } \div \frac{ {155}^{3} }{ {19}^{3} } = \\ \frac{ { - 155}^{4} }{ {19}^{2} } \times \frac{ {19}^{3} }{ {155}^{3} } = \\ - 155 \times 19 = - 2945$

7 0

3 years ago

While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between

mr_godi [17]

Answer: The expected value of the water depth is 4.5 m.

Step-by-step explanation:

Let x be a random variable which is uniformly distributed in interval [a,b] .

Then the mean of the distribution is ghiven by :-

$E(x)=\dfrac{a+b}{2}$

Given : While conducting experiments, a marine biologist selects water depths from a uniformly distributed collection that vary between 2.00 m and 7.00 m.

Then, the expected value of the water depth = $\dfrac{2+7}{2}=\dfrac{9}{2}=4.5$

Hence, the expected value of the water depth is 4.5 m.

4 0

3 years ago

Raj reads 7\12 of his book before dinner and another 2\12 of his book after dinner

lina2011 [118]

Answer:

he would have had read 9/12 of the book in total

Step-by-step explanation:

8 0

3 years ago

Solve!!!!!!!!!!!! Please

frozen [14]

Begin by multiplying everything by 3 to get rid of the fraction. That gives us $-2n \leq 48$ . The rule is when you divide by a negative, the direction of the sign changes, so we will end up with $n \geq -24$ . Because there is a line under the inequality sign, the circle is closed. So your choices are the second, fourth, and sixth.

6 0

4 years ago