Question answer please

Enrollment in French class at a high school is 0.72 of enrollment in Spanish class. What is enrollment in French class compared

emmasim [6.3K]

72%, 28%

1-0,72=0,38

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7 0

2 years ago

For the rhombus, what are the slopes of the two diagonals? DO NOT introduce any new variables.

Jobisdone [24]

The slopes of the two diagonals of the rhombus are: A. b - f/a - e and -a + e/b - f.

<h3>What is the Slope of a Line Segment?</h3>

To find the slope, the formula used is: change in y/change in x.

If two lines are perpendicular to each other, their slope values will be negative reciprocals.

<h3>What is the Diagonals of a Rhombus?</h3>

In a rhombus, the two diagonals in the rhombus bisects each other at angle 90 degrees. This means that the two diagonals of a rhombus are perpendicular to each other. Therefore, the slope of the diagonals of any rhombus would be negative reciprocals.

The slope of the diagonals of the rhombus given would therefore be negative reciprocals to each other.

Given two endpoints of one of the diagonals as:

(a, b) = (x1, y1)

(e, f) = (x2, y2)

Slope (m) = change in y / change in x = b - f/a - e

The negative reciprocal of b - f/a - e is -a + e/b - f.

Therefore, the slopes of the two diagonals are: A. b - f/a - e and -a + e/b - f.

Learn more about the slopes of diagonals of a rhombus on:

brainly.com/question/3050890

#SPJ1

5 0

1 year ago

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

maxonik [38]

Answer:

Total weight of the wheat placed on 45th square will be = $1.26\times 10^{6}tons$

Step-by-step explanation:

King rewarded the inventor of chess by giving grain of wheat on every square of the chess board. He places one grain of wheat on first square, 2 on second, 4 on 3rd, 8 on 4th and so on.

In fact he places grains of wheat in a progression S = 1, 2, 4, 8, 16.........n terms where value of n is 64.

We can rewrite the progression as S = 2°, 2, 2², 2³,.........n terms (n = 64)

In a geometric progression we know the nth term = $a(r^{n-1})$