All categories

3 years ago

I need 4 20 of fuel in %

Mathematics

2 answers:

ivanzaharov [21]3 years ago

7 0

Answer:

I think you meant 4/20 but thats 20%

Step-by-step explanation:

U don't have to put this on the calculator because 20 to be 100 you have to multiply it by 5. So 4 times 5 is 20 so its 20% hope I helped :DD

sdas [7]3 years ago

7 0

Answer:

20%

Step-by-step explanation:

4/20 can be tuned into a easier fraction that has 100 as a denominator.

So, 20*5=100 and 4*5=20 = 20/100

So the numerator is 20 meaning 20%

You might be interested in

Use the number line to add the fraction.

VLD [36.1K]

D 1/10

hope it helps!

4 0

3 years ago

When 27 times x squared times z all over negative 3 times x squared times z to the fourth power is completely simplified, the ex

snow_lady [41]

Isolate z by itself:

$\frac{z}{z^4}$

To simplify variables with powers, subtract the smaller power from the bigger power:

$4 - 1 = 3$
$\frac{z}{z^4} = \frac{1}{z^3} = z^{-3}$

The exponent will be -3.

4 0

3 years ago

Read 2 more answers

8. The volume of a cylinder is 942 cubic feet.

ikadub [295]

The radius would be 5 ft

7 0

3 years ago

Read 2 more answers

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. Match the pairs of polynomials to their products.

andreyandreev [35.5K]

The products of the polynomials are:

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6
(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²
(x - y) * (x + 3y) = x² + 2xy + 3y²
(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18
(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6
(x + 3y) * (x – 3y) = x² - 9y²

<h3>How to evaluate the products?</h3>

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9) = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9) = x²y² - 7xy + 3x²y - 27x - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3) = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²