Y = 1 + i
<span>(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i </span>
<span>(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i </span>
<span>1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i </span>
<span>1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i </span>
<span>-3 - 4i + k = -i </span>
<span>k = 4i - i + 3 </span>
<span>k = 3i + 3 </span>
<span>k = 3 * (1 + i) </span>
<span>k = 3y</span>
Answer:
Option B
Step-by-step explanation:
Taking the derivative of the residual function, then applying the normal equation:
[a; b] = (X'*X)^(X'*y)
with
X = [1 1; 2 1; 3 1; 4 1; 5 1]
X' is transpose of X
y = [11; 8; 4; 1; 0]
[a; b] = [-2.9 13.5]
Answer:
Thanks grll!!
Step-by-step explanation:
Answer:
(O,2)
Step-by-step explanation:
So I signed in to iReady did the question and got it right.
Answer:
p = 5
Step-by-step explanation:
We have that:

So

10/2 = 5
Then

Finding p:


