Find the missing term! if y=1+i, then y^3-3y^2+(-3y,-3y+1,3y,3i)-1=-i

1 answer:

4 0

Y = 1 + i

(1 + i)^3 - 3 * (1 + i)^2 + k - 1 = -i 
(1 + 3i + 3i^2 + i^3) - 3 * (1 + 2i + i^2) + k - 1 = -i 
1 + 3i - 3 - i - 3 - 6i + 3 + k - 1 = -i 
1 - 3 - 3 + 3 - 1 + 3i - i - 6i + k = -i 
-3 - 4i + k = -i 
k = 4i - i + 3 
k = 3i + 3 
k = 3 * (1 + i) 
k = 3y

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