Answer:
![\displaystyle\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
Step-by-step explanation:
It can work well to identify 4th powers under the radical, then remove them.
![\displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E6y%7D%7B128x%5E4y%5E5%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B16y%5E4%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B%282y%29%5E4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
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The applicable rules of exponents are ...
1/a^b = a^-b
(a^b)(a^c) = a^(b+c)
The x-factors simplify as ...
x^6/x^4 = x^(6-4) = x^2
The y-factors simplify as ...
y/y^5 = 1/y^(5-1) = 1/y^4
The constant factors simplify in the usual way:
24/128 = (8·3)/(8·16) = 3/16
Answer:
m∠B = 110°
Step-by-step explanation:
We know that,
The sum of the measures of the angles in a pentagon is 540°.
So, we get,
130 + (x-5) + (x+30) + 75 + (x-35) = 540
i.e. 3x + (130+30+75) - (5+35) = 540
i.e. 3x + 235 - 40 = 540
i.e. 3x + 195 = 540
i.e. 3x = 540 - 195
i.e. 3x = 345
i.e. x= 115°
Now, as m∠B = (x-5)° = (115-5)° = 110°
Hence, the measure of angle B is 110°.
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45 games i just used a calculator will u please mark me brainiest hope this helps :)
what question theres none
