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Step-by-step explanation:
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Hey there!
Here's your answer: m<BDC=69
Here's how I got it:<ADC=112; <ADB and <BDC together form <ABD.
you would add 6x+7and 12x-3 together to equal 112; 18x+4=112, and solve for x
next substitute 6 for x, into m<BDC=12x-3, and simplify!
Hope this helps!
Answer:
-1 and 0
Step-by-step explanation:
X ^4+x = 0;
x*(x^3+1)=0;
x*[(x^3-x)+(x+1)]=0;
x*[x(x-1)(x+1)+(x+1)]=0;
x*(x+1)(x^2-x+1)=0;
Since x^2-x+1=0 has no intersection with the X-axis, there is no x value such that y=0
x=0 or -1
Answer:
12
Step-by-step explanation:
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