Hello!
Do you see the line right in the middle of the box? That is the median. It points down to about 15.5
Our answer is D) 15.5.
I hope this helps!
Answer:
1, 2, 8, 128, 32768
Step-by-step explanation:

Thus the first five terms are: 1, 2, 8, 128, 32768.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59
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Answer:
Each player required 27.14 inches of fabric for their headband and wristband. 367.63in/39 players = 9.43in per wristband 761.53in/39 players+4 coaches = 17.71in per headband (17.71*39)+(9.34*39) = 1058.46 total fabric used for players only (1058.46)/39 = 27.14 inches of fabric used for each player individually
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First, what letter can it be at the beginning?
English Alphabet has 26 letters, so we have 26 possibilities
26*
then it can be any of 10 digits
26*10=260
then any of the remaining 9 digits:
26*10*9
then any of the remaining 8 and 7 digits:
26*10*9*8*7=131040
so the solution is: 131040 possible combinations!