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Ray Of Light [21]
3 years ago
11

Write (3x + 2)2 in expanded form using the polynomial identity (x + y)2 = x2 + 2xy + y2.

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0
(3x)^2 + 12x + 4


You're welcome.

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siniylev [52]

Answer:

B, (6hr. 40 min)

8 0
4 years ago
Please answer the following Question (35 Points)
never [62]

Answer:

Try the first one I think and I remember when I did this one but I forgot the answer to this

6 0
3 years ago
A car's rear windshield wiper rotates 140°. The total length of the wiper mechanism is 24 inches and the length of the wiper bla
Verizon [17]

Answer:

<h2>312.7 in^2</h2>

Step-by-step explanation:

This problem is on the mensuration of flat shapes, sectors and arc.

we know that the area of a sector is given as

A=(∅/360)*πr^2

Given that the length of the wiper R=24 in

and the length of the blade r= 16in

To find the area of the wiped surface we only require the length of the blade as the radius

The area of the wiped surface is given as= (140/360)*3.142*16^2

A= 0.3888*3.142*256

A=312.7 in^2

6 0
4 years ago
Please please help <br><br> Given the function f(x)=1/3x*2-3x+5 determine the inverse relation
yuradex [85]

The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

<h3>How to determine the inverse relation?</h3>

The function is given as

f(x)=1/3x^2-3x+5

Start by rewriting the function in vertex form

f(x) = 1/3(x - 9/2)^2 -7/4

Rewrite the function as

y = 1/3(x - 9/2)^2 -7/4

Swap x and y

x = 1/3(y - 9/2)^2 -7/4

Add 7/4 to both sides

x + 7/4= 1/3(y - 9/2)^2

Multiply by 3

3x + 21/4= (y - 9/2)^2

Take the square roots

y - 9/2 = √(3x + 21/4)

This gives

y = 9/2 + √(3x + 21/4)

Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

Read more about inverse functions at:

brainly.com/question/14391067

#SPJ1

5 0
2 years ago
Find all solutions to the equation (x² + 5x + 6)(x² − 3x − 4) = 0.
Soloha48 [4]

Answer:

The solutions are:

x=-2,\:x=-3,\:x=-1,\:x=4

Step-by-step explanation:

To find the solutions to the equation \left(x^2+5x+6\right)\left(x^2-3x-4\right)=0 you need to:

  • Factor \left(x^2+5x+6\right)

Break the expression into groups

x^2+5x+6=\left(x^2+2x\right)+\left(3x+6\right)

Factor out x from (x^2+2x)

x^2+2x=x\left(x+2\right)

Factor out 3 from 3x+6

3x+6=3\left(x+2\right)

x^2+5x+6=x\left(x+2\right)+3\left(x+2\right)\\\\\mathrm{Factor\:out\:common\:term\:}x+2\\\\x^2+5x+6=\left(x+2\right)\left(x+3\right)

  • Factor \left(x^2-3x-4\right)

x^2-3x-4=\left(x^2+x\right)+\left(-4x-4\right)\\\\x^2-3x-4=x\left(x+1\right)-4\left(x+1\right)\\\\x^2-3x-4=\left(x+1\right)\left(x-4\right)

Therefore

\left(x^2+5x+6\right)\left(x^2-3x-4\right)=\left(x+2\right)\left(x+3\right)\left(x+1\right)\left(x-4\right)=0

Using the Zero Factor Theorem:

5 0
4 years ago
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