Write (3x + 2)2 in expanded form using the polynomial identity (x + y)2 = x2 + 2xy + y2.

What is the value of x? Enter your answer in the box.

lubasha [3.4K]

Notice that based on the diagram, all of the sides of the triangle are the same length. (The dashes on the sides of the triangle show that the sides are of congruence.) This means that the triangle is an equilateral triangle. An important thing to note about equilateral triangles is that they all have angles of 60°. All angles in equivalent triangles are 60°.

This means that we can set $7x - 3$ equal to 60 to solve for $x$ :

$7x - 3 = 60$

Set up

$7x = 63$

Add 3 to both sides

$x = 9$

Divide both sides by 7

Our answer is x = 9.

8 0

3 years ago

IT IS EITHER A OR C BUT I DONT KNOW HICH ONE YoU WILL BE THE BRAINLIEST

maxonik [38]

The answer is A.

You can get this by modeling the function. It's slope and y intercept will yield the equation y = -.5x +1.5. Then you can try the ordered pairs in that, all of which work.

5 0

3 years ago

Ashley use 1/5 cup of winegar in her salad dressing recipe. How much

Papessa [141]

Answer:

I think the answer is 2/15 but I'm not a hundred percent sure

4 0

3 years ago

Communitative property of 20×72×5

Rasek [7]

The answer for this problem is 7,200

8 0

3 years ago

Read 2 more answers

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$

$\sigma = 3.5795$

See attachment for result of 1-VarStats

8 0

3 years ago