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1 year ago

Please please help Given the function f(x)=1/3x*2-3x+5 determine the inverse relation

Mathematics

1 answer:

yuradex [85]1 year ago

5 0

The inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

<h3>How to determine the inverse relation?</h3>

The function is given as

f(x)=1/3x^2-3x+5

Start by rewriting the function in vertex form

f(x) = 1/3(x - 9/2)^2 -7/4

Rewrite the function as

y = 1/3(x - 9/2)^2 -7/4

Swap x and y

x = 1/3(y - 9/2)^2 -7/4

Add 7/4 to both sides

x + 7/4= 1/3(y - 9/2)^2

Multiply by 3

3x + 21/4= (y - 9/2)^2

Take the square roots

y - 9/2 = √(3x + 21/4)

This gives

y = 9/2 + √(3x + 21/4)

Hence, the inverse relation of the function f(x)=1/3x*2-3x+5 is f-1(x) = 9/2 + √(3x + 21/4)

Read more about inverse functions at:

brainly.com/question/14391067

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What is the equation for the linear model in the scatter plot obtained by choosing the two points closest to the line?

HACTEHA [7]

Answer:

Option C is the answer.

Step-by-step explanation:

To find the equation of the straight line equation i.e, we must be given with the two points $\left (x_{1},y_{1} \right )$ and $\left (x_{2},y_{2}\right )$

Since from the graph the two points closest to the line are $\left ( 10,36 \right )$ and $\left ( 22,12 \right ).$

Equation of line with two points closest to the line :

$y-y_{1}=m\cdot \left ( x-x_{1} \right )$

where m is the slope.

First we find the slope(m)= $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$m=\frac{12-36}{22-10}$

on simplify we get, $m=-2$ .

Now, to find the equation of the line: $y-y_{1}=m\cdot \left ( x-x_{1} \right )$

$y-36=\left ( -2 \right )\cdot \left ( x-10 \right )$

Apply distributive property on right hand side, we get

$y-36=-2\cdot x+20$

Adding both sides by 36, we get

$y=-2x+20+36$

$y=-2x+56$ .

The equation for the linear model in the scatter plot obtained by the two closest point $\left ( 10,36 \right ) and \left ( 22,12 \right )$ closest to the line is,