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stealth61 [152]

3 years ago

11

The diagonal of a TV screen is 26 inches. The screen is 18.8 inches wide. How high is the screen? Round to the nearest hundredth

s place.

1 answer:

cluponka [151]3 years ago

8 0

26^2 = 18.8^2 + H^2
H^2 = 322.56
H = 17.96 inches

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A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide. A circle h

LuckyWell [14K]

The circumference of the outer edge of the path around the pool is 113.04 ft.

<h3>What is the circumference?</h3>

The Circumference (or) perimeter of circle = 2πR. where, R is the radius of the circle.

Given

A circular swimming pool has a radius of 15 ft.

There is a path all the way around that pool that is three feet wide.

A circle has a radius of 15 feet.

A larger circle goes around the smaller circle that is 3 feet wide.

The radius of the outer edge of the path around the pool = Radius of circle + width of outer circle.

The radius of the outer edge of the path around the pool = 15 + 3

The radius of the outer edge of the path around the pool = 18ft

The circumference of the outer edge of the path around the pool is;

$\rm Circumference=2\pi r\\\\Circumference = 2\times 3.14 \times 18\\\\Circumference=113.04 \ ft$

Hence, the circumference of the outer edge of the path around the pool is 113.04 ft.

To know more about circumference click the link given below.

brainly.com/question/5023328

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2 years ago

A store plans to sell two different game consoles, the Wii and the xbox. The store’s wholesale price for the Wii is $250, and th

Nimfa-mama [501]

Answer:

hi just need points

Step-by-step explanation:

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3 years ago

In 1859, 24 rabbits were released into the wild in Australia, where they had no natural predators. Their population grew exponen

Mashcka [7]

Answer:

a) P' = P

$P(t) = 24e^{0.693t}$ where t is step of 6 months

b) 7.7 years

c)1064.67 rabbits/year

Step-by-step explanation:

The differential equation describing the population growth is

$\frac{dP}{dt} = P$

Where t is the range of 6 months, or half of a year.

P(t) would have the form of

$P(t) = P_0e^{kt}$

where $P_0 = 24$ is the initial population

After 6 month (t = 1), the population is doubled to 48

$P(1) = 24e^k = 48$

$e^k = 2$

$k = ln(2) = 0.693$

Therefore $P(t) = 24e^{0.693t}$

where t is step of 6 months

b. We can solve for t to get how long it takes to get to a population of 1,000,000:

$24e^{0.693t} = 1000000$

$e^{0.693t} = 1000000 / 24 = 41667$

$0.693t = ln(41667) = 10.64$

$t = 10.64 / 0.693 = 15.35$

So it would take 15.35 * 0.5 = 7.7 years to reach 1000000

c. $P' = P_0ke^{kt}$

We need to resolve for k if t is in the range of 1 year. In half of a year (t = 0.5), the population is 48

$24e^{0.5k) = 48$

$0.5k = ln2 = 0.693$

$k = 1.386$

Therefore, $P' = 1.386*24e^{1.386t}$

At the mid of the 3rd year, where t = 2.5, we can calculate P'

$P' = 1.386*24e^{1.386*2.5} = 1064.67$ rabbits/year

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3 years ago

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