Question

Which of the following points is in the solution set of y < x2 - 2x - 8?(-2, -1)(0, -2)(4, 0)

Answer 1

Y < (x - 4)(x + 2)

so the critical points are -2 and 4
(-2,-1) will be in the solution

( 0,-2) will not 

(4,0) will not.
the answer is ((-2,-1)

Answer 2

Answer:

The correct option is 1. The point (-2,-1) is in the solution set of the given inequality.

Step-by-step explanation:

The given inequality is

$y$

A point (x₁,y₁) is in the solution set of above inequality if the inequality satisfy by the point (x₁,y₁).

Check the inequality by (-2,-1).

Put x=-2 and y=-1 in the given inequality.

$-1$

$-1$

$-1$

This statement is true, therefore the point (-2,-1) is in the solution set of the given inequality.

Check the inequality by (0,-2).

Put x=0 and y=-2 in the given inequality.

$-2$

$-2$

$-2$

This statement is false, therefore the point (0,-2) is not in the solution set of the given inequality.

Check the inequality by (4,0).

Put x=4 and y=0 in the given inequality.

$0$

$0$

$0$

This statement is false, therefore the point (4,0) is not in the solution set of the given inequality.