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kirill [66]
3 years ago
7

Which of the following points is in the solution set of y < x2 - 2x - 8?(-2, -1)(0, -2)(4, 0)

Mathematics
2 answers:
ratelena [41]3 years ago
5 0
Y < (x - 4)(x + 2)

so the critical points are -2 and 4
(-2,-1) will be in the solution

( 0,-2) will not 

(4,0) will not.
the answer is ((-2,-1)
dimulka [17.4K]3 years ago
4 0

Answer:

The correct option is 1. The point (-2,-1) is in the solution set of the given inequality.

Step-by-step explanation:

The given inequality is

y

A point (x₁,y₁) is in the solution set of above inequality if the inequality satisfy by the point (x₁,y₁).

Check the inequality by (-2,-1).

Put x=-2 and y=-1 in the given inequality.

-1

-1

-1

This statement is true, therefore the point (-2,-1) is in the solution set of the given inequality.

Check the inequality by (0,-2).

Put x=0 and y=-2 in the given inequality.

-2

-2

-2

This statement is false, therefore the point (0,-2) is not in the solution set of the given inequality.

Check the inequality by (4,0).

Put x=4 and y=0 in the given inequality.

0

0

0

This statement is false, therefore the point (4,0) is not in the solution set of the given inequality.

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3 years ago
It's a little blurry sorry please help
Ghella [55]

<u>Answer:</u>

It's X=2

<u>Working out:</u>

<u>(left one):</u>

2(x+3)=10

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Working out:

(right one):

2(x+3) must be all divided by 2 so it will be x+3 and same for 10, it will be 5 so...

x+3=5

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Hope it helps ^---^

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