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3 years ago

From the set {-282, -95, 95}, use substitution to determine which value of x makes the equation true.

Mathematics

1 answer:

Gwar [14]3 years ago

4 0

3X equals 285 a he Th jdfnxfncg

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If I have line segmants with the measurements 3in, 5 in and 8 in; can I make a triangle?

Dimas [21]

Answer:

Equilateral Triangle

Side a = 1

Side b = 1

Side c = 1

Angle ∠A = 60° = 1.0472 rad = π/3

Angle ∠B = 60° = 1.0472 rad = π/3

Angle ∠C = 60° = 1.0472 rad = π/3

C=60°B=60°A=60°b=1a=1c=1

Area = 0.43301

Perimeter p = 3

Semiperimeter s = 1.5

Height ha = 0.86603

Height hb = 0.86603

Height hc = 0.86603

Median ma = 0.86603

Median mb = 0.86603

Median mc = 0.86603

Inradius r = 0.28868

Circumradius R = 0.57735

Vertex coordinates: A[0, 0] B[1, 0] C[0.5, 0.86603]

Centroid: [0.5, 0.28868]

Inscribed Circle Center: [0.5, 0.28868]

Circumscribed Circle Center: [0.5, 0.28868]

Step-by-step explanation:

6 0

2 years ago

413×6<br> Please help meh in full work please

tatuchka [14]

Answer:

413x6=345467

Step-by-step explanation:

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20625%20%3D" id="TexFormula1" title="\sqrt{x} 625 =" alt="\sqrt{x} 625 =" align

Darina [25.2K]

Answer:

saaaa

Step-by-step explanation:

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4 0

3 years ago

What is the volume of a right circular cylinder in terms of Pi if its height measure 6 inches and the radius of its base is 2 in

docker41 [41]

V=hpir^2
r=2
h=6

v=6pi2^2
v=6pi4
v=24pi in³

5 0

3 years ago

A chemical flows into a storage tank at a rate of (180+3t) liters per minute, where t is the time in minutes and 0<=t<=60

Yuliya22 [10]

Answer:

The amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

Step-by-step explanation:

Consider the provided information.

A chemical flows into a storage tank at a rate of (180+3t) liters per minute,

Let $c(t)$ is the amount of chemical in the take at <em>t </em>time.

Now find the rate of change of chemical flow during the first 20 minutes.

$\int\limits^{20}_{0} {c'(t)} \, dt =\int\limits^{20}_0 {(180+3t)} \, dt$

$\int\limits^{20}_{0} {c'(t)} \, dt =\left[180t+\dfrac{3}{2}t^2\right]^{20}_0$

$\int\limits^{20}_{0} {c'(t)} \, dt =3600+600$

$\int\limits^{20}_{0} {c'(t)} \, dt =4200$

So, the amount of the chemical flows into the tank during the firs 20 minutes is 4200 liters.

5 0

3 years ago