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harina [27]
3 years ago
14

What kind of triangle is this?

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0
B. As all the sides are different lengths and angle f is bigger than 90 so it is obtuse
Hope this helps
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What’s the answer???
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Nikkis charges are 20,40,50,80. Dave’s charges are 25 and 37.5.
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Which statement about the function is true?
krok68 [10]

Answer:

The function is negative for all real values of x where -6< x < -2

Step-by-step explanation:

Given f(x) = (x + 2)(x + 6)

The graph of the function is as shown in the attached figure.

As shown, we can deduce the following:

The function is positive for all real values of x where x > -2 and x < -6

The function is zero at x = -2 and x = -6

The function is negative for all real values of x where -6 < x <-2

Compare the observations to the given statements:

So, The true statement is The function is negative for all real values of x where -6 < x <-2

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By what percent (%) will a fraction change if its numerator is decreased by 10% and its denominator is decreased by 70%?
grandymaker [24]
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7 0
3 years ago
Is domain of f(x,y) = 1 + (4 -y^2)^1/2 open, closed or neither<br><br> is it bounded or unbounded?
omeli [17]

Answer:

Closed and Bounded.

Step-by-step explanation:

Hi there!

1) Let's start by finding the values in which the function is defined. Remember that this can be rewritten:

f(x,y) = 1 + (4 -y^2)^{\frac{1}{2}} \:id\:est\:f(x,y)=1+\sqrt{(4 -y^2)}

Since every quadratic root are defined for values \geq 0  then, this help us to understand that we need calculate what interval this Domain is:

4-y^{2} \geq 0\\4-y^{2}-4\geq -4\\-y^{2}\geq-4 \\y^{2}\leq4\\-2\leq y\leq 2

D=[-2,2]

2) Graphically speaking, the domain is closed. For the values -2 and 2 are included, and bounded.

Bounded functions have all of their points contained by some circle origin centered. Check it out below.

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3 years ago
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