Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
<em>The answer is 0</em>
<em>So I think no solutions</em>
Step-by-step explanation:
You gotta get each equation into slope-intercept form, nd when u do that 9x - 3y = 6 turns into y = 3x - 2, nd 5y = 15x + 10 turns into y = 3x + 2. Add the equations together, nd get 0.
Answer:
Step-by-step explanation:
a. 4cm * 9cm * 2cm = 72 cm^3
b. 5m * 4m * 9m = 180 m^3
c. 10dm * 36 dm^2 (because the square could also be represented as 6cm * 6cm) =360 dm^3
d. (56mm)^3 = 175616 mm^3
e. 10 m * 1 m^2 (because of the square) = 10m^3
Answer:
12x^6y
Step-by-step explanation:
3 is the answer they are after 40