The factors of a polynomial function are the zeros of the function
It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
<h3>How to show why the x - 3 is a factor</h3>
The function is given as:
m(x) = x^3 - x^2 - 5x - 3
The factor is given as:
x - 3
Set the factor to 0
x - 3 = 0
Solve for x
x = 3
Substitute 3 for x in the function
m(3) = 3^3 - 3^2 - 5(3) - 3
Evaluate
m(3) =0
Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3
Read more about factors at:
brainly.com/question/11579257
Answer:
Given below
Step-by-step explanation:
The algebraic identity is (a-b)^2
= a^2 + b^2 - 2ab
So it'll be,
(x-4)^2
= x^2 + (4)^2 - (2)(x)(4)
= x^2 -8x + 16
or x^2 +16 -8x
Answer:A number decreased by 40
Step-by-step explanation: I really don't feel like explaining this lol...
Answer:
Step-by-step explanation: Answer is A
