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4 years ago

12

Given the following polynomial find the maximum possible number of turning points. f(x)=x^11+x^10+x^12+x^9

1 answer:

11111nata11111 [884]4 years ago

5 0

Turning points are inflection points

think
1st degree (linear) has no turning/inflecion points
2nd degree (quadratic, parabola) has 1 turning/inflection point
so
nth degree has n-1 turning/inflection point

this is 11th degree since highest power is 12
12-1=11
11 turning oints

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Citrus2011 [14]

Answer:

(-2,3)

so the a answer is -2 on the x axis

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3 years ago

Solve for m: 0.02m+0.08(8-m) = 1.78

marusya05 [52]

m = 3.07

The given equation is:

0.02m + 0.08(8-m) = 1.78

Expand the equation using the distribution rule:

0.02m + 0.64m - 0.08m = 1.78

Simplify the Left Hand Side

0.58m = 1.78

Divide both sides by 0.58

0.58m / 0.58 = 1.78 / 0.58

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Learn more here: brainly.com/question/19253676

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3 years ago

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3 years ago

Question mark 1: Match the triangle to correct function and answer

postnew [5]

Answer:

Triangle 1 - $m\angle A = 58^{\circ}$ , hypotenuse = 16

$x \approx 8.479$

Triangle 2 - $m \angle A = 44^{\circ}$ , adjacent leg = 18

$x \approx 17.382$

Triangle 3 - $m\angle A = 49^{\circ}$ , opposite leg = 12

$x \approx 15.900$

Step-by-step explanation:

Each triangle is solved by means of trigonometric relations:

Triangle 1 - $m\angle A = 58^{\circ}$ , hypotenuse = 16

$\cos 58^{\circ} = \frac{x}{16}$

$x = 16\cdot \cos 58^{\circ}$

$x \approx 8.479$

Triangle 2 - $m \angle A = 44^{\circ}$ , adjacent leg = 18

$\tan 44^{\circ} = \frac{x}{18}$

$x = 18\cdot \tan 44^{\circ}$

$x \approx 17.382$

Triangle 3 - $m\angle A = 49^{\circ}$ , opposite leg = 12

$\sin 49^{\circ} = \frac{12}{x}$

$x = \frac{12}{\sin 49^{\circ}}$

$x \approx 15.900$

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A) Gravity Because gravity moves and makes the earth move

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3 years ago

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