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Phoenix [80]
3 years ago
11

On a trip, you had to change your money from dollars to British pounds. You got 560 pounds for 800 dollars. Which is a unit rate

that describes the exchange?
1 3/5 pounds per dollar
0.625 pounds per dollar
1 3/7 pounds per dollar
0.7 pound per dollar
Mathematics
2 answers:
Olin [163]3 years ago
5 0

Answer:0.7

Step-by-step explanation:

charle [14.2K]3 years ago
3 0
<span>If we got 560 pounds for 800 dollars and x pounds for 1 dollar, this means that x = 560*1/800 <=> x = 56/80. Performing the calulation we get that x = 0.7 . So the right answer is the final one.</span>
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How do you find the fraction of 0.35
SOVA2 [1]

Answer:

\frac{7}{20}

Step-by-step explanation:

0.35 is the same as 35/100

which can be simplified to 7/20

4 0
2 years ago
Relationship B has a greater rate than Relationship A. This graph represents Relationship A.
tester [92]

Answer:

Rate in relationship A = (6 - 3)/(8 - 4) = 3/4 = 0.75

For Table A: Rate = (3 - 1.2)/(5 - 2) = 1.8/3 = 0.6

For table B: Rate = (3.5 - 1.4)/(5 - 2) = 2.1/3 = 0.7

For table C: Rate = (4 - 1.6)/(5 - 2) = 2.4/3 = 0.8

For table D: Rate = (2 - 1.5)/(4 - 3) = 0.5/1 = 0.5

Therefore, the correct answer is option C.

4 0
2 years ago
Using the least common denominator rename 3/5 and 1/20
UkoKoshka [18]
LCD is 20
3/5 -> 12/20
1/20 -> 1/20
5 0
2 years ago
Read 2 more answers
Futhe Mathematics<br><img src="https://tex.z-dn.net/?f=%28Cos%20%7B%7D%5E%7B4%7Dt%20-Sin%20%7B%7D%5E%7B4%7Dt%20%29%20%20%5Cdiv%2
Nastasia [14]

Answer:

cos2t/cos²t

Step-by-step explanation:

Here the given trigonometric expression to us is ,

\longrightarrow \dfrac{cos^4t - sin^4t }{cos^2t }

We can write the numerator as ,

\longrightarrow \dfrac{ (cos^2t)^2-(sin^2t)^2}{cos^2t }

Recall the identity ,

\longrightarrow (a-b)(a+b)=a^2-b^2

Using this we have ,

\longrightarrow \dfrac{(cos^2t + sin^2t)(cos^2t-sin^2t)}{cos^2t}

Again , as we know that ,

\longrightarrow sin^2\phi + cos^2\phi = 1

Therefore we can rewrite it as ,

\longrightarrow \dfrac{1(cos^2t - sin^2t)}{cos^2t}

Again using the first identity mentioned above ,

\longrightarrow \underline{\underline{\dfrac{(cost + sint )(cost - sint)}{cos^2t}}}

Or else we can also write it using ,

\longrightarrow cos2\phi = cos^2\phi - sin^2\phi

Therefore ,

\longrightarrow \underline{\underline{\dfrac{cos2t}{cos^2t}}}

And we are done !

\rule{200}{4}

Additional info :-

<em>D</em><em>e</em><em>r</em><em>i</em><em>v</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em> </em><em>o</em><em>f</em><em> </em><em>c</em><em>o</em><em>s</em><em>²</em><em>x</em><em> </em><em>-</em><em> </em><em>s</em><em>i</em><em>n</em><em>²</em><em>x</em><em> </em><em>=</em><em> </em><em>c</em><em>o</em><em>s</em><em>2</em><em>x</em><em> </em><em>:</em><em>-</em>

We can rewrite cos 2x as ,

\longrightarrow cos(x + x )

As we know that ,

\longrightarrow cos(y + z )= cosy.cosz -  siny.sinz

So that ,

\longrightarrow cos(x+x) = cos(x).cos(x) - sin(x)sin(x)

On simplifying,

\longrightarrow cos(x+x) = cos^2x - sin^2x

Hence,

\longrightarrow\underline{\underline{cos (2x) = cos^2x - sin^2x }}

\rule{200}{4}

7 0
2 years ago
Choose the function that correctly identifies the transformation of f(x) = x2 shifted two units to the left and one unit down.
AnnZ [28]

Answer:

D) g(x) = (x + 2)^2 - 1



7 0
3 years ago
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