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aleksley [76]
4 years ago
6

How many pennies could you have if:

Mathematics
1 answer:
BartSMP [9]4 years ago
5 0

Answer:

The number of pennies are 91 pennies

Step-by-step explanation:

The given parameters are

When we split the pennies in twos the number left = 1

When the pennies are split in 3s the number left = 1

When the pennies are split in 5s the number left = 1

When the pennies are split in 7 the number left = 0

Therefore, 7 is a factor of the number

Given that when the pennies are split in 5s the number left = 1, the number ends with a 1

We have the products of 7 ending with 1 from Excel as 21 and 91, 161...

We check 91 given 21 is directly divisible by 3 as follows;

91/2 = 45 remainder 1

91/3 = 30 remainder 1

91/5 = 18 remainder 1

91/7 = 13 remainder 0

Therefore, the number of pennies are 91 pennies.

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3 years ago
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liraira [26]
<h2>Explanation:</h2><h2></h2>

The Fundamental Theorem of Algebra states the following:

<em>For</em><em> </em><em>any polynomial of degree n we will have n roots.</em>

<em />

So the general form of the equation of a polynomial is:

A \ \mathbf{polynomial \ function} \ of \ x \ with \ degree \ n \ is \ given \ by:\\ \\ f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\ldots +a_{2}x^{2}+a_{1}x+a_{0} \\ \\ where \ n \ is \ a \ nonnegative \ integer \ and \ a_{n}, a_{n-1}, \ldots a_{2}, a_{1}, a_{0} \\ with \ a_{n}\neq

Since our polynomial will have exactly 11 roots, then the equation will have the following form:

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