Answer:
Option 4, 64 cm^2
Step-by-step explanation:
The polygon in the shape of a star can be made to be easier to find the area of by cutting it into triangle. For all the "point edges" of the star, we can cut them in half from the vertex to create two right-angled triangles at each edge.
The formula of the area of a triangle is bh/2: the height is given as 6cm, the base is 4cm /2 (after you cut it in half) and so is 2 cm. Since the edges can be cut into two, there are 8 right angled triangles at the edges in total.
To find the area of them:
A=8(bh/2)=8(2*6/2)=48 cm^2
However, we are still missing the part at the centre we haven't found the area of, the square. The area of a square is given by the square of the side length(4cm). Thus, A=4*4=16cm^2
Adding the areas of all the edges and the square:
48 + 16 = 64cm^2
Hence, the area of the polygon is 64cm^2
Answer: w=−4
Step-by-step explanation:
hoped this helped
200+90+8+.02 is the correct answer
Answer:
Step-by-step explanation:
If 
, then 
. It follows that
![\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%20%5C%5C%5Cfrac%7Bg%28x%2Bh%29-g%28x%29%7D%7Bh%7D%20%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Ccdot%20%5Bg%28x%2Bh%29%20-%20g%28x%29%5D%20%5C%5C%26%3D%20%5Cfrac%7B1%7D%7Bh%7D%20%5Cleft%28%20%5Cfrac%7B1%7D%7Bx%2Bh%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%5Cright%29%5Cend%7Baligned%7D)
Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.
Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.
For f(t) = 3 sin(t), the minimum is -3, the maximum is 3.
For additional information:
The period T of the function y=3sin(4t) is;
The period of y = 3 sin (4t) is (2pi) / 4 = pi / 2
The sine function with amplitude A = 0.75 and period T = 10, is
y = 0.75 sin( (2pi / 10) x )
= 0.75 sin( (pi/5) t)
y(4) = 0.75 sin( (pi/5) (4) )
= 0.75 sin ( (4/5) pi ) = .4408
Drawing the sine and cosine function on the same plot shows
that they are identical except for a horizontal shift.
The cosine
function leads the sine function by a shift of (2pi/4) = pi/2.
For the last part, y(4) = 0.75 cos( (2pi/10) (4) ) = - 0.6067
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