Total pressure is constant and PT = P = 1/2*ρ*v^2
So p1 + 1/2*ρ*v1^2 = p2 + 1/2*ρ*v2^2 and from continuity we have ρ*A1*v1 = ρ*A2*v2
So v2 = v1*A1/A2 since r2 = 2r1 then A2 = 4A1
so v2 = v1/4
Now from above p2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v2^2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v1^2/4^2
So p2 = 3.0x10^4Pa + 1/2*1000kg/m^3*(12m/s)^2 - 1/2*1000kg/m^3*12^2/16
= 9.75x10^4Pa = 9.8x10^4Pa
Answer:
The length is 4 times the width
Median, upper quartile, and maximum are all incorrect
Let's first say that L=W+44
and then remember that perimeter is P=2L+2W
replace the L with W+44
we then get P=2(W+44)+2W, now I'll solve it
P=2W+88+2W
P=4W+88
substitute 288 for P
288=4W+88
200=4W
50=W
so now we now how wide the court is. add 44 to find the length which gives you L=94
as always plug the numbers back into your perimeter equation to ensure L and W are correct
Factors of 15: 1, 3, 5, 15
<span>Factors of 45: 1, 3, 5, 9, </span>15, 45
<span>The Greatest common factor is 15.</span>
