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abruzzese [7]
3 years ago
9

Which of the following sets of angles sum to 180°? picture included, please help.

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

Choice 3

Step-by-step explanation:

add 63 and 64 which gives you 127. Then you subtract 180 and 127. This gives you 53. 63+53+64=180. Know that the angle is 180 degrees too so you don't even have to do math.

SSSSS [86.1K]3 years ago
5 0
ACF, BGH this makes a lot of sense bc i’m in alegbra 1 and ik what i’m doing! thanks
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1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
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Answer:

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x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

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Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

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f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

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The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

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The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

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The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

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So the root is x = 4/9

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x = 0 is local minimum, x = 4/9 is absolute maximum.

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